September 28, 2026 at 1:04 pm #5599 Lösung: à base acide conique H2O OH– H3O+ HS– S2- H2S F– x HF H2PO–4 HPO2-4 H3PO4 PO-34 x HPO2-4 H3PO4 H2PO–4 x NH3 NH–2 NH+4 NO–2 x HNO2