Lösung:
{a) } -_(P3)_(P3)<`/>`\ | {1,1- dimetilciclopropano} |
{b) } /<`|><_(A75)>\/ | {2,2- dimetilbutano} |
{c) } @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; @n(7,90)\@n(6,90)/<`|>@n(5,90)\@n(4,90)/@n(3,90)\<_p3><@n(2,90)\@n(1,90)>/ | {2,2,5-Tri-metil-heptano} |
{d) } @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; @n(9,90)/@n(8,90)\@n(7,90)/@n(6,90)\@n(5,-90)|@n(4,90)<`/|>\@n(3,-90)<|>/@n(2,90)<\>`|@n(1,-90) | {4-Ethyl-2,3-Di-Methyl-Nonan} |
{e) } @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; @n(5,90)/@n(4,90)<`|O|>\@n(3,90)/@n(2,90)\@n(1,-90)|O`| | {4- Oxo-pentan-al} |
{f) } @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; @n(6,90)\@n(5,90)/@n(4,90)<`|>\@n(3,-90)<|@n(2,90)<`/@n(1,90)>\NH2>/OH | {2-Amino-4- Metil…Hexan-3-ol} |
{g) } @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; @n(10,90)/@n(9,90)\@n(8,90)/<`|>@n(7,90)\@n(6,-90)|@n(5,90)<`/>\@n(4,-90)<|OH>/@n(3,90)\@n(2,-90)<|@n(1,90)>/NH2 | {2-Amino-5,7-Di-metil-Decan-4-ol} |
{h) } @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; HO/@n(1,90)<`|O|>\@n(2,90)/@n(3,90)<`|>\@n(4,-90)<|`/@n(6,-90)<`\H2N>|<`/@n(8,90)>\>/\ | {6-Amino-4-Ethyl-3,7″Di metil-Octan-1-Carbono acido} |
{i)} /<`|>\/\/ | {2-Methylhexan } |
{j) } /<`|>\<|>/<`|>\ | {2,3,4-Trimethylpentan } |
{k) } /\<|>/\/\ | {3- metilheptano } |
{l) } /\<_(A150)><|OH>/\ | {3-Methyl-3- pentanolo } |
{m) } Br\<|>/\/ | {2- Brompentan } |