Lösung:
{a: } /<`|>\/\/ | {kC} |
{b: } /<`|>\<|>/<`|>\ | {kc} |
{c: } @:n(n,a,L:.2)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; /\@n(*,-90)<|>/\/\ | {} |
{d: } /\<_(A150)><|OH>/\ | {kC} |
{e: } @:n(n,a,L:.2)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; Br\@n(*,-90)<|>/\/ | {} |
{f: } OH`\`|O|`/|`/`\`|//\|\O|`/O/\ | {kC} |
{g: } @:n(n,a,L:.2)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; @n(*,-110)-<_(a30,N2)O>_q3O_q3<>_(a30) | {} |
{h: } @:n(n,a,L:.2)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; OH|`/|<@n(*,0)\OH>`/<@n(*,-90)|OH>`\@n(*)<`/HO>`|`\O\/O\@n(*,-60) | {} |
{i: } @:n(n,a,L:.2)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; `/O`\`/O/`|//\|@n(*)\/`||`\`// | {} |
{j} @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; ||`/`\<`/HO>`|<`\HO>//\/<>@n(*,90)<_(A-90,w)OH>\/N<_(y-.5)H>\CH3 | {} |
{j} @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; @n(*,90)\|`//<|>`\`/O/`|/`|`\c\/ | {} |
{k} @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; @:n(n,a,L:.4)<_(A&a,L&L,N0)$itemColor1(blue)\"&n\">@; `|@n(*,45, 0.3)/@n(*,90):a\|_#1@n(*,90)`/@n(*,-90, 0.2)`\@n(*,90)`/@n(*,45)<`|>|`/`\@n(*,90)<`/HO>`|/\|0\\/`|`\0`|/\`|; #a`|<`\>@n(*,-90, 0.2)/\/\<|>/ | {} |