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Calculate the following: Density:
- Calculate The Density the following: Gases: O2, N2 and CO2 In the case of Normal conditions
- Calculate The Density The Air
- Explanation, Why? a Fire with a CO2-Löscher deleted will be can.
Lösung: Notes: Normal conditions In the case of Gases That's right.: a mol claimed 22.4 L
This means that Applicable: n = 1, V = 22.4 L
From Density=m/V and n=m/M following:: D=n·M/V- Density = m/V = n·N/V
Dichte(CO2)= 1mol·M(CO2)/22.4 L = 44/22.4= 1.96 g/L
Dichte(O2) = 32/22.4 = 1.43 g/L
Dichte(N2) = 28/22.4 = 1.25 g/L - Air of which: to 80% from N2 and 20% O2
Components N2: 80% One of them Manufacture in which all the materials used are:: 0.8 mol
Components O2: 20% One of them Manufacture in which all the materials used are:: 0.2 mol
Dichte(Luft) = (0.8·M(N2)+0.2·M(O2))/22.4 = (0.8·28+0.2·32)/22.4 = 1.29 g/L - The Density of CO2 is 1.96 g/L, of The Air 1.29 g/L. This means that is CO2 'Heavier' How The Air and displaced This means that This 'lighter' O2 (Density 1.43 g/L), The Flame suffocated, There you go. not Oxygen to the Candle flame Infiltration can.
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