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Assessments and Reasons, In the case of which Substance a higher boiling point to Expected would be.
{a) } HF { Responsibility. } HCl{b) } H2O { Responsibility. } H2S
Solution: - HF is Polar as HCl, Because … :
HF: ΔEN 1.8 , HCl: ΔEN 1.4
Therefore,: Sdp(HF) > Sdp(HCl)
experiment: Sdp(HF) = 20°C, Sdp(HCl) = -84°C, - H2O Polar as H2S, Because …
H2O: ΔEN 1.3 , H2S: ΔEN 0.2
Therefore,: Sdp(H2O) > Sdp(H2S)
experiment: Sdp(H2O) = 100°C, Sdp(H2S) = -60°C,
One of them Other, very more important Point is, that HF and from H2O in each case hydrogen bonds with The Commission to form can. Therefore, lying their The Court of Auditors I 'm sure . also higher.
- HF is Polar as HCl, Because … :
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