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Given are the following: molecules. It is for each Partial task It ‘s just … a molecule given, This is it. to be – where applicable possible – hydrogen bonds between The Molecules Registered will be.
Are for each Partial task two various molecules given, This is it. to be – where applicable possible – hydrogen bonds between The Both different Molecules Registered will be.
The not Binding Electron pairs are Here you go. as Double points Registered.{a) } {Water}{b) } H2O + NH3{c) } NH3{d) } HF{e) } CH3OH{f) } CH3OCH3{g) } CH3F
Solution: {a) } H2O + H2O{:}H-$dots(RB)O<`|H> _(x2,y,H)H-$dots(RB)O<`|H>{b) } H2O + NH3{:}H-$dots(BR)O<`|H> _(x2,y,H)H-$dots(R)N<`|H><|H>{b) … or }H-$dots(B)N<`|H>-H_(x2,y,H) $dots(LR)O<`|H>|H{b) … or }H|$dots(LB)O-H_(x2,y,H) $dots(L)N<`|H><|H>-H{c) } NH3+ NH3{:}H-$dots(R)N<`|H><|H> _(x2,y,H)H-$dots(R)N<`|H><|H>{d) } HF + HF{:}H-$dots(TRB)F _(x2,y,H)H-$dots(TRB)F{e) } CH3OH + CH3OHH-C<`|H><|H>-$dots(TB)O-H_(x2,y,H) $dots(LB)O<`|H>-C<`|H><|H>-H{f) } H-C<`|H><|H>-$dots(TB)O-C<|H><`|H>-H{No H-BrOats and oats possible, H not to O Binded}{g) } H-C<`|H><|H>-$dots(TBR)F{No H-BrOats and oats possible, H not to F Binded}
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