← Zurück zur vorhergehenden Übersicht: Chemisches Gleichgewicht
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Given are the following reactions. Equal each reaction from, So that …
… whole (!) Figures as Coefficients occurring
… for each Substance their Rate of speed (d[X]/(i) the number of) indicated will be.
a) Br2 + H2 ⇄ HBr
b) N2O5 → NO2 + O2
c) A + 2 B → 3 C + 4 D (Yes, I did. Balanced!)
Lösung: a) Br2 + H2 ⇄ 2·HBr
-d[Br2]/dt = -d[H2]/dt = + 1/2·d[HBr]/dt
b) 2·N2O5 → 4·NO2 + 1·O2
-1/2·d[N2O5]/dt = + 1/4·d[NO2]/dt = + d[O2]/dt
c) A + 2·B → 3·C + 4·D
– d[A]/(i) the number of = -1/2·d/dt = + 1/3·d[C]/dt = + 1/4·d[D]/dt
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