Supposedly equal to molecules, But Different Weight, radioactivity (Radio-09)

By The reaction of Bromine with Hydrogen is generated Bromine hydrogen gas (HBr). The following: isotopes participating The Commission to The reaction: ¹H, ²H, ⁷⁹Br and ⁸¹Br .

1. How is The Balanced reaction equation?
2. How many various HBr-molecules with of different Weight will be In this case of which:?
3. What ? Isotope combination would be This The easiest HBr, which This most severe HBr-molecule? Indication Including molar mass

Assumptions for The molar masses: They Calculated The Commission with The Simplification, that m(Proton) = m(Neutron). This means that Applicable the following::
M(¹H) = 1 g/mol, M(²H) = 2 g/mol, M(⁷⁹Br) = 79 g/mol and and M(⁸¹Br) = 81 g/mol.

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• September 29, 2026 at 8:36 pm #9350
    Aufgabe: Radio-09    

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  By The reaction of Bromine with Hydrogen is generated Bromine hydrogen gas (HBr). The following: isotopes participating The Commission to The reaction: ¹H, ²H, ⁷⁹Br and ⁸¹Br .

  1. How is The Balanced reaction equation?
  2. How many various HBr-molecules with of different Weight will be In this case of which:?
  3. What ? Isotope combination would be This The easiest HBr, which This most severe HBr-molecule? Indication Including molar mass

  Assumptions for The molar masses: They Calculated The Commission with The Simplification, that m(Proton) = m(Neutron). This means that Applicable the following::
  M(¹H) = 1 g/mol, M(²H) = 2 g/mol, M(⁷⁹Br) = 79 g/mol and and M(⁸¹Br) = 81 g/mol.

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    Aufgabe: Radio-09    

  ⓘ    🔄 Reload     🖨️ print           ◀  –   ▶     ?! Question/Answer ?!

  By The reaction of Bromine with Hydrogen is generated Bromine hydrogen gas (HBr). The following: isotopes participating The Commission to The reaction: ¹H, ²H, ⁷⁹Br and ⁸¹Br .

  1. How is The Balanced reaction equation?
  2. How many various HBr-molecules with of different Weight will be In this case of which:?
  3. What ? Isotope combination would be This The easiest HBr, which This most severe HBr-molecule? Indication Including molar mass

  Assumptions for The molar masses: They Calculated The Commission with The Simplification, that m(Proton) = m(Neutron). This means that Applicable the following::
  M(¹H) = 1 g/mol, M(²H) = 2 g/mol, M(⁷⁹Br) = 79 g/mol and and M(⁸¹Br) = 81 g/mol.

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  September 29, 2026 at 8:36 pm #9351
  Lösung:

  1. H₂ + Br₂ ⇄ 2 · HBr
  2. Es is given 4 various possible Pairs:
         ¹H-⁷⁹Br, ¹H-⁸¹Br, ²H-⁷⁹Br and ²H-⁸¹Br
  3. M(¹H-⁷⁹Br) = 80 g/mol, M(¹H-⁸¹Br) = 82 g/mol, M(²H-⁷⁹Br) = 81 g/mol, M(²H-⁸¹Br) = 83 g/mol
         lightweight molecule ¹H-⁷⁹Br, most difficult molecule ²H-⁸¹Br

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