Loss of mass 2 (Radio-51)

Es will be a Grams 23592U in full Split.
a) Calculate The freeing Energy for each Grams. Proposed Split Nuclear energy will be in each case One Energy of 200 MeV Free.

    Notes: 1of which: = 1.602·10^-19 J

b) How high could It's with This Energy a Car (m = 1000 kg) lifting?

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• September 29, 2026 at 8:36 pm #9382
    Aufgabe: Radio-51    

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  Es will be a Grams 23592U in full Split.
  a) Calculate The freeing Energy for each Grams. Proposed Split Nuclear energy will be in each case One Energy of 200 MeV Free.

      Notes: 1of which: = 1.602·10^-19 J

  b) How high could It's with This Energy a Car (m = 1000 kg) lifting?

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    Aufgabe: Radio-51    

  ⓘ    🔄 Reload     🖨️ print           ◀  –   ▶     ?! Question/Answer ?!

  Es will be a Grams 23592U in full Split.
  a) Calculate The freeing Energy for each Grams. Proposed Split Nuclear energy will be in each case One Energy of 200 MeV Free.

      Notes: 1of which: = 1.602·10^-19 J

  b) How high could It's with This Energy a Car (m = 1000 kg) lifting?

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  September 29, 2026 at 8:36 pm #9383
  Lösung:

  1. n = m/M
  2. n( 23592U) = m( 23592U)/M( 23592U) = 1 g/235 g/mol = 0.0043 mol
  3. real Number of: 6.022·10²³·0.0043 = 2.563·10²¹ Atoms
  4. for each Divisions 200 MeV Responsibility. 200·10⁶·1.602·10^-19 J = 3.204·10^-11 J

  a) Total So what do you mean? 2.56·10²¹ · 3.204·10^-11 J = 8.21·10¹⁰ J
  b) With The Energy can What ? made will be, z.B. something . lifting: E=m·g·h

      h =E/(m·g) = 8.21·10¹⁰/(1000·10) = 8210000 m = 8210 km

      to the Comparison HWhat are you doing? Mount Everest about. 8 km on Sea, So what do you mean? 1000· Car lifting

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