Loss of mass 3 (Radio-52)

Es will be a Grams 23592U in full Split. Proposed Grams will be about. 8.21·10¹⁰ J Energy Free, Look at this. In addition also One previously exercise. The Switzerland required in The the last 5 years Average round 810'000 Terahjoule Energy for each year. Supposedly, These Energy would like to It's exclusively with The Divisions of 23592U winning. How Large would be One This is the case for 'Uranium ores'?
FThe Commission shall adopt a decision. The calculation will be Other Dates Required:

1. 1 Terahjoule = 10¹² Joule, Containing by weight:: 8.1·10¹⁷ J
2. Other Sources Speaking of 2.04·10¹⁷ J
3. Density Uranium ores 19.1 g/cm³

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• September 29, 2026 at 8:36 pm #9384
    Aufgabe: Radio-52    

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  Es will be a Grams 23592U in full Split. Proposed Grams will be about. 8.21·10¹⁰ J Energy Free, Look at this. In addition also One previously exercise. The Switzerland required in The the last 5 years Average round 810'000 Terahjoule Energy for each year. Supposedly, These Energy would like to It's exclusively with The Divisions of 23592U winning. How Large would be One This is the case for 'Uranium ores'?
  FThe Commission shall adopt a decision. The calculation will be Other Dates Required:

  1. 1 Terahjoule = 10¹² Joule, Containing by weight:: 8.1·10¹⁷ J
  2. Other Sources Speaking of 2.04·10¹⁷ J
  3. Density Uranium ores 19.1 g/cm³

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    Aufgabe: Radio-52    

  ⓘ    🔄 Reload     🖨️ print           ◀  –   ▶     ?! Question/Answer ?!

  Es will be a Grams 23592U in full Split. Proposed Grams will be about. 8.21·10¹⁰ J Energy Free, Look at this. In addition also One previously exercise. The Switzerland required in The the last 5 years Average round 810'000 Terahjoule Energy for each year. Supposedly, These Energy would like to It's exclusively with The Divisions of 23592U winning. How Large would be One This is the case for 'Uranium ores'?
  FThe Commission shall adopt a decision. The calculation will be Other Dates Required:

  1. 1 Terahjoule = 10¹² Joule, Containing by weight:: 8.1·10¹⁷ J
  2. Other Sources Speaking of 2.04·10¹⁷ J
  3. Density Uranium ores 19.1 g/cm³

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  September 29, 2026 at 8:36 pm #9385
  Lösung:

  1. Terahjoule = 10 ¹²J
         Annual consumption 810'000 Terahjoule = 0.81·10⁶ TJ = 0.81·¹⁸ J = 8.1·10¹⁷ J
  2. for each Grams 8.21·10¹⁰ J
         necessary Weight: 8.1·10¹⁷ J / 8.21·10¹⁰ J = 9.87·10⁶ Grams
  3. Density = D = m/V
         V = m/D = 9.87·10⁶ g / 19.1 g/cm³ = 516'754 cm³
  4. V(Kugel) = 4/3·pi·r³
         r = 3-Root from (3·V/4·pi) = (3·516754/4·pi)^0.33333 = 49.7 cm
         The Diameters The Bullets is So what do you mean? about. 1 Meters

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