Gap text of electrolysis (Salze-83)

In the following text, the gaps a) , b) , c) etc. are to be meaningfully filled.

If you immerse two graphite electrodes in a zinc-coded solution and apply an equal voltage, an electric current flows. At the electrode connected to the minus pole, metallic zinc is formed, and at the electrode connected to the plus pole, iodine is separated. The processes running in the solution are now considered more closely.

Two electrodes plunge into the zinc-coding solution. One of these is directly connected to the minus pole, so it's loaded to a) . This electrode is called b) . It has an electron surplus and therefore attracts c) ions. These ions are called d) , in this example they are Zn²⁺ ions. From the secretion of zinc at the e) we can conclude that the zinc ions the cathode f) and become g) . Zn²⁺ + h) → h) .
The electrode connected to the pluspole is called A , it is charged B . It lacks electrons, so it attracts C) . These ions are called D) . For example, I^-ions (iodidions). Apply to the anode And then they're going to break down each one of these into E and they're going to become iodine atoms that bind together into biatomic F .
2 G) → 2 I + G) ; 2 I → G)

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• October 16, 2026 at 4:42 am #9452
    Exercise: Salze-83    

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  In the following text, the gaps a) , b) , c) etc. are to be meaningfully filled.

  If you immerse two graphite electrodes in a zinc-coded solution and apply an equal voltage, an electric current flows. At the electrode connected to the minus pole, metallic zinc is formed, and at the electrode connected to the plus pole, iodine is separated. The processes running in the solution are now considered more closely.

  Two electrodes plunge into the zinc-coding solution. One of these is directly connected to the minus pole, so it's loaded to a) . This electrode is called b) . It has an electron surplus and therefore attracts c) ions. These ions are called d) , in this example they are Zn²⁺ ions. From the secretion of zinc at the e) we can conclude that the zinc ions the cathode f) and become g) . Zn²⁺ + h) → h) .
  The electrode connected to the pluspole is called A , it is charged B . It lacks electrons, so it attracts C) . These ions are called D) . For example, I^-ions (iodidions). Apply to the anode And then they're going to break down each one of these into E and they're going to become iodine atoms that bind together into biatomic F .
  2 G) → 2 I + G) ; 2 I → G)

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    Exercise: Salze-83    

  ⓘ    🔄 Reload     🖨️ print           ◀  –   ▶     ?! Question/Answer ?!

  In the following text, the gaps a) , b) , c) etc. are to be meaningfully filled.

  If you immerse two graphite electrodes in a zinc-coded solution and apply an equal voltage, an electric current flows. At the electrode connected to the minus pole, metallic zinc is formed, and at the electrode connected to the plus pole, iodine is separated. The processes running in the solution are now considered more closely.

  Two electrodes plunge into the zinc-coding solution. One of these is directly connected to the minus pole, so it's loaded to a) . This electrode is called b) . It has an electron surplus and therefore attracts c) ions. These ions are called d) , in this example they are Zn²⁺ ions. From the secretion of zinc at the e) we can conclude that the zinc ions the cathode f) and become g) . Zn²⁺ + h) → h) .
  The electrode connected to the pluspole is called A , it is charged B . It lacks electrons, so it attracts C) . These ions are called D) . For example, I^-ions (iodidions). Apply to the anode And then they're going to break down each one of these into E and they're going to become iodine atoms that bind together into biatomic F .
  2 G) → 2 I + G) ; 2 I → G)

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  October 16, 2026 at 4:42 am #9453
  Solution:

  1. (a) negative
  2. (b) Cathode
  3. (c) positively charged
  4. (d) cations
  5. (e) Cathode
  6. (f) Electrons
  7. (g) Zinc seeds
  8. h) Zn²⁺ + 2e^– → Zn
  9. A) [translation unavailable]
  10. B) positive
  11. C) negative loaded ions
  12. D) Anions
  13. E) an electron
  14. F) Iodine molecules
  15. G) 2I^– → 2 I + 2 e^– ; 2 I → I₂

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