In the following text, the gaps a) , b) , c) etc. are to be meaningfully filled.
If you immerse two graphite electrodes in a zinc-coding solution and you apply an equal voltage, an electric current flows. the metallic zinc which is connected to the minus pole is formed and iodine is separated from the electrode which is connected to the plus pole. The processes under way in the solution will now be examined more closely.
Two electrodes plunge into the zinc-coding solution, one of which is connected by a conductor to the minus pole, which charges it to a . It has a surplus of electrons, so it attracts c ions. as d) , in the example are Zn2+-IonenFrom the secretion of zinc at the e) it can be concluded that the zinc ions the cathode f) and to g) to become VIP2. Zn2+ + h) → Vip2-h) to Vip2. The electrode connected to the plus pole is called A , it's charged B . These ions are called D . I– -Ⅰons (iodides) at the anode And then they're going to break down each one of these into E and they're going to become iodine atoms that bind together into biatomic F . 2 V2 – V2 – V2 → 2 I + G) ; 2 I → V2 – V2 – V2