← Zurück zur vorhergehenden Übersicht: Redox_en
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The following, already balanced reaction equation is given. Determine all oxidation numbers. Where does the oxidation take place, where is the reduction?
What ‘s so special about this place ?Cl2 + 2NaOH -> NaCl + NaClO + H2O
Solution: Cl(0)2 + 2Na(+i)O(-ii)H(i) -> Na(+i)Cl(-i) + Na(+i)Cl(i)O(-ii) + H(+i)2O(-ii){Cl: } {0} -> {-I} {: reduction}{Cl: } {0} -> {+I} {: Oxidation}{H: } {+I} -> {+I} {: no change}{Na: } {+I} -> {+I} {: no change}{O: } {-II} -> {-II} {: no change}So it is observed that the chlorine is oxidized and reduced at the same time! In such a case in point is of a disproportion speaking. And for specialists, the reverse reaction is called co-proportionation or syn-proportionation.
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