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What voltage is calculated for the Daniell element if at 298 K the concentration of the zinc sulphate solution is 0.001 mol/L and that of the copper sulphate solution is 0.8 mol/L.
Solution: - Observation: Zn → Zn2+
· c(reduzierte Form) = c(Zn) = 1.0 (solids)
· c(oxidierte Form) = c(Zn2+)
· E1(Zn/Zn2+)=-0.76 + 0.059/2·log(c(Zn2+)/c(Zn))
· E1 = -076 + 0.059/2·log(0.001/1) = -0.849 V - Monitoring and monitoring Cu2+ → Cu
· c(reduzierte Form) = c(Cu) (solids)
· c(oxidierte Form) = c(Cu2+)
· E2(Cu/Cu2+)=0.35 + 0.059/2·log(c(Cu2+)/c(Cu))
· E2 = 0.35 + 0.059/2·log(0.8/1.0) = +0.347 V - ΔE = EKathodenreaktion – EAnodenreaktion
· The cathode reaction is defined as a reduction
· Reduction: Cu2+ → Cu, which is E2
· ΔE = E2 – E1 = 0.347-(-0.849)=1.196 V
- Observation: Zn → Zn2+
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