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How long must a electricity the strength 0.45 A flow, so that from a CuCl2 solution 3.5 g copper discharged are?
Note : identical exercise also at the same time, subjects salts.
Solution: - CuCl2: Ions Cu2+ or Cl–
Cu2+ + 2e– → Cu, z = 2 - m/M = I·t/(z·F)
t = m·z·F/(M·I) = 3.5·2·96485/(63.546·0.45)
t = 23618 s = about 6.6 h
- CuCl2: Ions Cu2+ or Cl–
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