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Glucose (C6H12O6) can Different Implemented will be: Aerobic (with O2) and other (without O2).
Formulation for Both reactions The reaction equation and Calculate in each case The Standard reaction enthalpy.
Notes I: where applicable The ΔHof Unknown are, and then Calculate In general with x, y and so on.
Notes II: state of matter specify
Lösung: ΔHof(C6H12O6) = -1268 kJ/mol
ΔHof(O2)(g) = 0 kJ/mol
ΔHof(C2H5OH)(l) = -278 kJ/mol
ΔHof(H2O)(g) = -286 kJ/mol
ΔHof(CO2) = -393 kJ/mola) Combustion reaction:
C6H12O6 + 6·O2(g) ⇄ 6·CO2(g) + 6·H2O(l)
ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
ΔHoR = (6·-393 + 6·-286)-(-1268+6·0) = – 2806 kJ/molb) GOther articles:
C6H12O6 ⇄ 2·C2H5OH(l) + 2·CO2(g)
Notes: C2H5OH the name The Commission Alcohol
ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
ΔHoR = (2·-278 + 2·-393)-(-1268) = – 74 kJ/mol
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