Lösung:
Note: The ion product applies to any concentration, pH or p.OH.
Ionic product: c(H3O+)·c(OH–) = 10-14 mol2/l2
| c(H3O+ mol/l) | c(OH– mol/l) | pH | pOH |
| Strong0.001 = 10-3} | 10-11 | 3 | 11 |
| Strong0.01 = 10-2} | 10-12 | 2 | 12 |
| 10-13 | Strong0.1 (10-1)} | 13 | 1 |
| 10-14/0.2 = 5·10-14 | Strong0.2 } | 13.3 | 0.7 |
| 10-12 | 10-2= 0.01 | Strong12} | 2 |
| 10-3 = 0.001 | 10-11 | 3 | Strong11} |