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One liter of two solutions A and B with the same starting pH of 4.8. A is a hydrochloric acid solution, B is an acidic acid solution.
Now one liter of water is added to each solution.- Calculate the new pH of solution A and B
- In the case of a solution that has a greater change in pH,
Please note: HCl is a strong acid (pKs) < 0), acetic acid a weak acid (pKs) > 0)
Lösung: Based on the pH value, it can now be used for the strong acid HCl and for the faint acidic acid the concentration is calculated:
- High acidity: HCl
pH = -log(c(H3O+)), c(H3O+) = 10-pH = 0.000015 mol/l
C = n/V or n = c · V
n = 0.000015 · 1.0 l = 0.000015 mol - Weak acid: acetic acid
pH = 1/2(pKs log)(HA)), c(HA) = …
n = c·V = - Now every solution becomes 1 L of pure water is admitted, with c=n/V resulting the following:
- HCl: pH = -log(c(H3O+)) = -log(n/V)
pH = log
… not finished yet !
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