September 28, 2026 at 1:04 pm #5603
Lösung:
{a) Acide acide: } | CH3COOH + H2O <=> CH3COO^- + H3O^+ |
{b) Acide salé:} | HCl + H2O <=> Cl^- + H3O^+ |
{(c) l'acide formique: } | HCOOH + H2O <=> HCOO^- + H3O^+ |
{d) L'acide sulphurique: } | H2SO4+ 2H2O <=> SO4^2- + 2H3O^+ |
{e) L'acide salpétrique: } | HNO3+ H2O <=> NO3^- + H3O^+ |
{e) L'acide carbonique: } | H2CO3+ 2H2O <=> CO3^2- + 2H3O^+ |