Reply To:Structural forecasting, task 1 (oc-50) The following results of an elementary analysis are given: 12.79%. H 2.15%, the rest is bromine What is the sum formula Draw the molecule based on the sum formula. How could this be expected? NMR the (both!) structures?

Lösung:

Note to the percentages: these are always mass percentages. Let's go from 100 Gram of substance

1. Adopted 100 Grams, therefore 12.79 g C, 2.15 g H and 85.07 g Bromine
2. n(C) = 12.79/12 = 1.07 mol ≈ 1 mol
3. n(H) = 2.15/1 = 2.15 mol ≈ 2 mol
4. N (Br) = 85.07/79.9 = 1.07 mol ≈ 1 mol
5. {So what do you mean? } CH2Br { But it can't be drawn, octet rule}
6. {This means that} (CH2Br)2 {The Commission shall adopt delegated acts in accordance with this Article.} C2H4Br2
7. Characteristically, there are two ways to make the bromine atoms at the same C or per carbon atom per one bromateon
8. Br\/\Br { } /<`|Br>\Br