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The following equation is given. If it is equal, determine all the oxidation numbers, where does the oxidation occur, where does the reduction occur?
Ag + HNO3 ⇄ AgNO3 + NO2 + H2O
Solution: Ag + 2HNO3 -> AgNO3 + NO2 + H2OAg(0) + 2H(+i)N(+v)O3(-ii) -> Ag(+i)N(+v)O(-ii)3 + N(+iv)O(-ii)2 + H(+i)2O(-ii){Ag: } {0} -> {+I} {Oxidation}{N: } {+V} -> {+IV} {Reduction}{H: } {+I} -> {+I} {No change}{O: } {-II} -> {-II} {No change}
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