Redox, reaction 4 (Redox-16) The following, already balanced reaction equation is given. Determine all oxidation numbers. Where does the oxidation take place, where is the reduction? 3SO3^2- + Cr2O7^2- + 8H^+ -> 2Cr^3+ + 3SO4^2- + 4H2O

  Exercise: Redox-16    

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The following, already balanced reaction equation is given. Determine all oxidation numbers. Where does the oxidation take place, where is the reduction?

3SO3^2- + Cr2O7^2- + 8H^+ -> 2Cr^3+ + 3SO4^2- + 4H2O

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Solution:

{} 3S(+iv)O3(-ii)^2- + Cr(+vi)2O7(-ii)^2- + 8H(+i)^+ -> 2Cr(+iii)^3+ + 3S(+vi)O4(-ii)^2- + 4H(+i)2O(-ii)

{S: } {+IV} -> {+VI} {Oxidation}

{Cr: } {+VI} -> {+III} {Reduction}

{H: } {+I} -> {+I} {No change}

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