Redox, reaction 5 (Redox-17)

Subsequent, already balanced reaction equations are given. Determine all oxidation numbers. Where does the oxidation take place, where does the reduction take place? If the oxidation number does not change, indicate this as well.

{a: } 3SO3^2- + Cr2O7^2- + 8H^+ -> 2Cr^3+ + 3SO4^2- + 4H2O

{b: } N2H4 + 4Fe(CN)6^3- + 4OH^- -> N2 + 4Fe(CN)6^4- + 4H2O

{c: } Ru + 6Cl^- + 3NO3^- + 6H^+ -> RuCl6^3- + 3NO2 + 3H2O

{d: } ClO3^- + 3SO2 + 3H2O -> 3SO4^2- + Cl^- + 6H^+

{e: } 3H2S + 2HNO3 -> 2NO + 3S + 4H2O

{f: } KSCN + 4H2O + 4I2 -> KHSO4 + 7HI + ICN

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• October 16, 2026 at 4:42 am #9486
    Exercise: Redox-17    

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  Subsequent, already balanced reaction equations are given. Determine all oxidation numbers. Where does the oxidation take place, where does the reduction take place? If the oxidation number does not change, indicate this as well.
  

  {a: } 3SO3^2- + Cr2O7^2- + 8H^+ -> 2Cr^3+ + 3SO4^2- + 4H2O

  {b: } N2H4 + 4Fe(CN)6^3- + 4OH^- -> N2 + 4Fe(CN)6^4- + 4H2O

  {c: } Ru + 6Cl^- + 3NO3^- + 6H^+ -> RuCl6^3- + 3NO2 + 3H2O

  {d: } ClO3^- + 3SO2 + 3H2O -> 3SO4^2- + Cl^- + 6H^+

  {e: } 3H2S + 2HNO3 -> 2NO + 3S + 4H2O

  {f: } KSCN + 4H2O + 4I2 -> KHSO4 + 7HI + ICN

  ---

  
  

    Exercise: Redox-17    

  ⓘ    🔄 Reload     🖨️ print           ◀  –   ▶     ?! Question/Answer ?!

  Subsequent, already balanced reaction equations are given. Determine all oxidation numbers. Where does the oxidation take place, where does the reduction take place? If the oxidation number does not change, indicate this as well.
  

  {a: } 3SO3^2- + Cr2O7^2- + 8H^+ -> 2Cr^3+ + 3SO4^2- + 4H2O

  {b: } N2H4 + 4Fe(CN)6^3- + 4OH^- -> N2 + 4Fe(CN)6^4- + 4H2O

  {c: } Ru + 6Cl^- + 3NO3^- + 6H^+ -> RuCl6^3- + 3NO2 + 3H2O

  {d: } ClO3^- + 3SO2 + 3H2O -> 3SO4^2- + Cl^- + 6H^+

  {e: } 3H2S + 2HNO3 -> 2NO + 3S + 4H2O

  {f: } KSCN + 4H2O + 4I2 -> KHSO4 + 7HI + ICN

  ---

  ---

  October 16, 2026 at 4:42 am #9487
  Solution:

  {a: } 3S(+iv)O(-ii)3^2- + Cr(+vi)2O(-ii)7^2- + 8H(+i)^+ -> 2Cr(+iii)^3+ + 3S(+vi)O(-ii)4^2- + 4H(+i)2O(-ii)

  $itemColor1(white){empty} {S: } {IV} -> {VI} {: Oxidation}

  $itemColor1(white){empty} {Cr: } {VI} -> {III} {: reduction}

  $itemColor1(white){empty} {H: } {+I} -> {+I} {: no change}

  $itemColor1(white){empty} {O: } {-II} -> {-II} {: no change}

  {b:} N(-ii)2H(+i)4 + 4Fe(+iii)(C(+ii)N(-iii))6^3- + 4O(-ii)H(+i)^- -> N(0)2 + 4Fe(+ii)(C(+ii)N(-iii))6^4- + 4H(+i)2O(-ii)

  $itemColor1(white){empty} {N: } {-II} -> {0} {: Oxidation}

  $itemColor1(white){empty} {Fe: } {+III} -> {+II} {: reduction}

  $itemColor1(white){empty} {H: } {+I} -> {+I} {: no change}

  $itemColor1(white){empty} {C: } {+II} -> {+II} {: no change}

  $itemColor1(white){empty} {O: } {-II} -> {-II} {: no change}

  {c:} Ru(0) + 6Cl(-i)^- + 3N(+v)O(-ii)3^- + 6H(+i)^+ -> Ru(+iii)Cl(-i)6^3- + 3N(+iv)O(-ii)2 + 3H(+i)2O(-ii)

  $itemColor1(white){empty} {Ru: } {0} -> {+III} {: Oxidation}

  $itemColor1(white){empty} {N: } {+V} -> {+IV} {: reduction}

  $itemColor1(white){empty} {Cl: } {-I} -> {-I} {: no change}

  $itemColor1(white){empty} {H: } {+I} -> {+I} {: no change}

  $itemColor1(white){empty} {O: } {-II} -> {-II} {: no change}

  {d:} Cl(+v)O3(-ii)^- + 3S(+iv)O2(-ii) + 3H2(+i)O(-ii) -> 3S(+vi)O4(-ii)^2- + Cl(-i)^- + 6H(+i)^+

  $itemColor1(white){empty} {Cl: } {+V} -> {-I} {: reduction}

  $itemColor1(white){empty} {S: } {+IV} -> {+VI} {: Oxidation}

  $itemColor1(white){empty} {H: } {+I} -> {+I} {: no change}

  $itemColor1(white){empty} {O: } {-II} -> {-II} {: no change}

  {e:} 3H(+i)2S(-ii) + 2H(+i)N(+v)O(-ii)3 -> 2N(+ii)O(-ii) + 3S(0) + 4H(+i)2O(-ii)

  $itemColor1(white){empty} {S: } {-II} -> {0} {: Oxidation}

  $itemColor1(white){empty} {N: } {+V} -> {+III} {: reduction}

  $itemColor1(white){empty} {H: } {+I} -> {+I} {: no change}

  $itemColor1(white){empty} {O: } {-II} -> {-II} {: no change}

  {f:} K(+i)S(-ii)C(iv)N(-iii) + 4H(+i)2O(-iii) + 4I(0)2 -> K(+i)H(+i)S(+vi)O(-ii)4 + 7H(+i)I(-i) + I(+i)C(+ii)N(-iii)

  $itemColor1(white){empty} {S: } {-II} -> {+VI} {: Oxidation}

  $itemColor1(white){empty} {C: } {+IV} -> {+II} {: reduction}

  $itemColor1(white){empty} {I: } {O} -> {-I} {: reduction}

  $itemColor1(white){empty} {K: } {+I} -> {+I} {: no change}

  $itemColor1(white){empty} {H: } {+I} -> {+I} {: no change}

  $itemColor1(white){empty} {O: } {-II} -> {-II} {: no change}

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