Notes to The Percentage data: in this case Acting It ‘s The Commission Always to Percentage by weight. With this The Accounting simpler will be, Going We are of 100 Grams Substance from

1. Adopted 100 Grams, This means that 12.79 g C, 2.15 g H and 85.07 g Bromine
2. n(C) = 12.79/12 = 1.07 mol ≈ 1 mol
3. n(H) = 2.15/1 = 2.15 mol ≈ 2 mol
4. n(Br) = 85.07/79.9 = 1.07 mol ≈ 1 mol
5. {So what do you mean? } CH2Br { It’s not The Commission But not drawing, octet rule}
6. {This means that} (CH2Br)2 {Responsibility.} C2H4Br2
7. Drawing is given It ‘s two MOther articles and articles, The Bromine atoms on the equal to C or for each Carbon atom The Commission a Manufacture from materials of any heading
8. Br\/\Br { } /<`|Br>\Br

Given are the following: Results One of them elemental analysis: C 12.79%. H 2.15%, The Remains be Bromine

1. How is The molecular formula
2. Drawing This molecule by: The molecular formula. What ? falling on?
3. How See ? This to Expected NMR The (Both!) Structures from?

Es are the following: Products of condensation reaction given. Drawing The Scalpeline formulas The This is the case for Educated by analogy to the the first Example. Please note:, that The Notation with a Retrosynthesis arrow made has been. Go on . by analogy before.

Go on . In the case of each exercise The following masses before:
– Drawing The requested(n) molecules with The Functional Groups
– Let it go. The Both drawn molecules with each other reacting
– In addition to the Product Water is generated One new functional Group. What ??
– Each of them Partial task It should be at least: three times solved will be
Notes: The molecules to be Neutral be

1. Two identical Alcohol reacting with each other
2. Two Different Alcohol reacting with each other
3. One of them Alcohol reacts with One of them carboxylic acid
4. Two identical Carbonic acids reacting with each other
5. Two Different Carbonic acids reacting with each other
6. One of them Amina reacting with One of them carboxylic acid

LManufacture in which all the materials used are: Look at this. In the case of exercise oc-41

Given are the following: molecules. Let it go. These in One of them condensation reaction with each other reacting.

Given are the following: Structures. How can The Substances from The This is the case for Hydrogenated hydrocarbons Manufacture will be? Write The This is the case for (Stable) Intermediate steps I ‘m going .. To the Part of must to The the right Place Reduced (Responsibility. Oxidated) will be, These Technical Difficulties Applicable It ‘s But to This Place not to take into account.
Sample solution given In the case of Example a). Please note: also, that The Notation with a Retrosynthesis arrow made has been. Go on . by analogy before.