Structure Predictions, exercise 1 (oc-50) Given are the following: Results One of them elemental analysis: C 12.79%. H 2.15%, The Remains be Bromine How is The molecular formula Drawing This molecule by: The molecular formula. What ? falling on? How See ? This to Expected NMR The (Both!) Structures from?

  Aufgabe: oc-50    

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Given are the following: Results One of them elemental analysis: C 12.79%. H 2.15%, The Remains be Bromine

1. How is The molecular formula
2. Drawing This molecule by: The molecular formula. What ? falling on?
3. How See ? This to Expected NMR The (Both!) Structures from?

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Lösung:

Notes to The Percentage data: in this case Acting It ‘s The Commission Always to Percentage by weight. With this The Accounting simpler will be, Going We are of 100 Grams Substance from

1. Adopted 100 Grams, This means that 12.79 g C, 2.15 g H and 85.07 g Bromine
2. n(C) = 12.79/12 = 1.07 mol ≈ 1 mol
3. n(H) = 2.15/1 = 2.15 mol ≈ 2 mol
4. n(Br) = 85.07/79.9 = 1.07 mol ≈ 1 mol
5. {So what do you mean? } CH2Br { It’s not The Commission But not drawing, octet rule}
6. {This means that} (CH2Br)2 {Responsibility.} C2H4Br2
7. Drawing is given It ‘s two MOther articles and articles, The Bromine atoms on the equal to C or for each Carbon atom The Commission a Manufacture from materials of any heading
8. Br\/\Br { } /<`|Br>\Br

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