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Topic Testing
All problems and solutions as
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All problems and solutions as
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- test (testen-01)Zum Teil gibt es folgende Konstrukte nicht, aber Testseite, gucken wie die Darstellung funktioniert:
2x, 2abc, 3·4def, 4def, 73, 7(a-b), 7(3·4)
(abc)2 , (abc)-2 , [abc]2, [abc]-2
(abc)def , (abc)-def , [abc]def, [abc]-def
72, 7-2, (7)2, (7)-2, (7)2-, [7]2, [7]2-, [7]-2, [7]2- abc
abcdef , abcdef
Ionenprodukt: c(H3O+)·c(OH–) = 10-14 mol2/l2
a2 + b3 + d·e-2 = f+3 – (e33)
(a)2 + (b3) + (d·e)-2 = f+3 – (e33)
Einheiten … [kg/m3], m/s2, [mol/l]–, g/cm3
Ableitungen1 -d[Br2]/dt = -d[H2]/dt = + 1/2·d[HBr]/dt
Ableitungen2 -1/2·d[N2O5] /dt = + 1/4·d[NO2]/dt = + d[O2]/dt
Ableitungen3 – d[A]/dt = – 1/2·d[B]/dt = + 1/3·d[C]/dt = + 1/4·d[D]/dt
Ableitungen4 -½ d[N2O5]/dt = + 1/4 d[NO2]/dt = + d[O2]/dt
– d[A]/dt = – ½ [dB]/dt = + 1/3 d[C]/dt = + 1/4 d[D]/dt
E-Schreibweise 5·102, 5·10-2, 5·102
Test2 c(H2SO4) > c(HSO–4 ) > c(SO2-4 )
Test3 H2SO4 > HSO–4 > SO2-4 …… SO2-4 , SO-24, SO2-4 , SO24
Test3 H2SO4 ……. HSO–4 …. SO2-4
Test4 (abc)2
Mehratomige Ionen NH+4, SO2-4 , SO-24, SO2-4 , SO24, NO–3, H2PO–4
normal .. C6H12O6, H2O, CO2, e+, e–, p+, p–, 13C, Mg2+, (Mg2+), (F-), (C6H12O6)
Kerne: 1H, 4He, 92U, 73Li, 42He2+, 42He+2
Beta-Minus: 10n → 11p + 0-1e–
Beta-Plus: 11p → 10n + 01e+
Mehratomige Ionen NH+4, SO2-4 , SO-24, SO2-4 , SO24, NO–3, H2PO–4
… noch mehr CO2-3 , CO-23 , HCO–3 , HSO–4 , OH–, H3O+, (H3O+) , H3O+
plus-Ladungen Na+ / Na2+ / Na+2 / Na3+ / Na+3 / 92U+ / 92U2+ / 92U+2
minus-Ladungen Br– / Br2- / Br-2 / Br3- / Br-3 / Br4- / O– / O-1 / O1-
diverses =header= _abs_ e–, ee–, ab–, AB–, CDE–, CDe–, p+, Br– , Na+, Cl–, H3O+, OH–,
Komplexe [Fe(H2O)6]–, [Fe(H2O)6]3-, [Fe(H2O)6]-3,[Fe(H2O)6]+, [Fe(H2O)6]2+, [FeS]2+, [FeS2]2
Komplexe2 [Fe(H2O)6]x, [Fe(H2O)6]y,[Fe(H2O)6]?
Test pH = log(c(H3O+)), 82Br–,
Klammerdinge (13C), ( 42He), 42He, ( 42He2+), ( 42He+2), (Mg2+), (Mg+2)
Thermodynamik ΔHof(C6H12O6), ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
Thermo 2: ΔHoR(H2O), ΔSoR(CO2), ΔSoR= So(Produkte) – So(Edukte)
Thermo 3: ΔHoR(H2O), So(CO2), So(C6H12O6), So(Edukte), So(Produkte)
Thermo 4: ΔSoR= So(Produkte) – So(Edukte)
Thermo 4a: ΔSoR = So(H2O)
Thermo 5: dG = dH – T·dS
Thermo 6: ΔGoR = ΔHoR – T· ΔSoR
Thermo 7: ΔGoR, ΔGoR(H2O)
Und hier sollte eine Tabelle kommen:Stoff M(g/mol) m(g) n(mol) H2O 18 100 100/18= 5.55 H2 2 2·5.55 = 11.1 5.55 O2 32 32·2.77 = 88.9 5.55 / 2 = 2.77 O3 32 32·2.77 = 88.9 5.55 / 2 = 2.77
Und hier sollte eine Liste kommen:- b) Text und noch Text
- Text und noch Text
- b) Text und noch Text
- Text und noch Text
- b) Text und noch Text
- _@_ Text und noch Text mehr
- _@_ Text und noch Text mehr
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- chemieformeln (testen-02)
A small article in Chemistry
Confirmation test for iron II
3K3[Fe(CN)6] + 3Fe^2+ -> 3KFe(ii)[Fe(iii)(CN)6]”|v” + 6K^+Curcumin
`\`/<`\H3C`O>|<`/HO>\/`|_o/\/<`||O>\/<`||O>\//\/\(*/`OCH3*)|<\OH>`/`\`|_o
…….. nochmals ….
A small article in Chemistry
Confirmation test for iron II
3K3[Fe(CN)6] + 3Fe^2+ -> 3KFe(ii)[Fe(iii)(CN)6]”|v” + 6K^+Curcumin
`\`/<`\H3C`O>|<`/HO>\/`|_o/\/<`||O>\/<`||O>\//\/\(*/`OCH3*)|<\OH>`/`\`|_o
…….. nochmals ….
H2O orH2SO4/\OHdies und das - 1
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- An dieser Stelle kommt die ganze Frage, aber kurz formuliertAn dieser Stelle kommt die neue Frage, aber auch ein Update ist natürlich möglich. Fortsetzung der Frage (im Inputfile) auf einer neuen Zeile. Auch können explizite Zeilenumbrüche gemacht werden:
(testen-03)
Des Weiteren ist die chemische Notation relativ einfach: Fe3+, SO2-4, 235U, ^235 U (Leerschlag), 23692U, 6.022·1023 (sollte gleich dargestellt werden: 6.022·1023)
Fehler? SO24 vs. SO2+4 vs. SO+24 - 1
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- à l’essai (testen-01)Pour Partie Il y a Il les suivants: Les constructions pas, Mais c'est Page d'essai, à regarder comme Les Présentation fonctionne:
2x, 2abc, 3·4def, 4def, 73, 7(a-b), 7(3·4)
(abc)2 , (abc)-2 , [abc]2, [abc]-2
(abc)def , (abc)-def , [abc]def, [abc]-def
72, 7-2, (7)2, (7)-2, (7)2-, [7]2, [7]2-, [7]-2, [7]2- abc
abcdef , abcdef
produit ionique: c(H3O+)·c(OH–) = 10-14 mol2/l2
a2 + b3 + d·e-2 = f+3 – (e33)
(a)2 + (b3) + (d·e)-2 = f+3 – (e33)
Unités … [kg/m3], m/s2, [mol/l]–, g/cm3
Ableitungen1 -d[Br2]/dt = -d[H2]/dt = + 1/2·d[HBr]/dt
Ableitungen2 -1/2·d[N2O5] /D'autre part, = + 1/4·d[NO2]/dt = + d[O2]/dt
Ableitungen3 – d[A]/D'autre part, = – 1/2·d[B]/dt = + 1/3·d[C]/dt = + 1/4·d[D]/dt
Ableitungen4 -½ d[N2O5]/dt = + 1/4 d[NO2]/dt = + d[O2]/dt
– d[A]/D'autre part, = – ½ [Db]/D'autre part, = + 1/3 d[C]/D'autre part, = + 1/4 d[D]/D'autre part,
E-En écriture 5·102, 5·10-2, 5·102
Le test2 c(H2SO4) > c(HSO–4 ) > c(SO2-4 )
Le test3 H2SO4 > HSO–4 > SO2-4 …… SO2-4 , SO-24, SO2-4 , SO24
Le test3 H2SO4 ……. HSO–4 …. SO2-4
Le test4 (abc)2
Le nombre de points Les ions NH+4, SO2-4 , SO-24, SO2-4 , SO24, NO–3, H2PO–4
de façon normale .. C6H12O6, H2O, CO2, e+, e–, p+, p–, 13C, Mg2+, (Mg2+), (F-), (C6H12O6)
Le noyau: 1H, 4He, 92U, 73Li, 42He2+, 42He+2
Les résultats de l'enquête: 10n → 11p + 0-1e–
Le beta-plus: 11p → 10n + 01e+
Le nombre de points Les ions NH+4, SO2-4 , SO-24, SO2-4 , SO24, NO–3, H2PO–4
… d'autres plus CO2-3 , CO-23 , HCO–3 , HSO–4 , OH–, H3O+, (H3O+) , H3O+
Charges supplémentaires Na+ / Na2+ / Na+2 / Na3+ / Na+3 / 92U+ / 92U2+ / 92U+2
Charges négatives Br– / Br2- / Br-2 / Br3- / Br-3 / Br4- / O– / O-1 / O1-
divers =header= _abs_ e–, ee–, ab–, AB–, CDE–, CDe–, p+, Br– , Na+, Cl–, H3O+, OH–,
Les complexes [Fe(H2O)6]–, [Fe(H2O)6]3-, [Fe(H2O)6]-3,[Fe(H2O)6]+, [Fe(H2O)6]2+, [FeS]2+, [FeS2]2
Les complexes2 [Fe(H2O)6]x, [Fe(H2O)6]y,[Fe(H2O)6]?
Le test pH = log(c(H3O+)), 82Br–,
D'autres pièces de rechange (13C), ( 42He), 42He, ( 42He2+), ( 42He+2), (Mg2+), (Mg+2)
thermodynamique ΔHof(C6H12O6), ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
Thermo 2: ΔHoR(H2O), ΔSoR(CO2), ΔSoR= So(Produkte) – So(Edukte)
Thermo 3: ΔHoR(H2O), So(CO2), So(C6H12O6), So(Edukte), So(Produkte)
Thermo 4: ΔSoR= So(Produkte) – So(Edukte)
Thermo 4a: ΔSoR = So(H2O)
Thermo 5: dG = dH – T·dS
Thermo 6: ΔGoR = ΔHoR – T· ΔSoR
Thermo 7: ΔGoR, ΔGoR(H2O)
Il y a aussi Je suis ici. devrait être une Tableau à venir:Tissu M(g/mol) m(g) n(mol) H2O 18 100 100/18= 5.55 H2 2 2·5.55 = 11.1 5.55 O2 32 32·2.77 = 88.9 5.55 / 2 = 2.77 O3 32 32·2.77 = 88.9 5.55 / 2 = 2.77
Il y a aussi Je suis ici. devrait être une Liste à venir:- b) Le texte et d'autres Le texte
- Le texte et d'autres Le texte
- b) Le texte et d'autres Le texte
- Le texte et d'autres Le texte
- b) Le texte et d'autres Le texte
- _@_ Le texte et d'autres Le texte plus
- _@_ Le texte et d'autres Le texte plus
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- b 15 (testen-15)
- Typ: Double-Dreieck
- … Double-Dreieck etc. ….
- Text bbb
- Text ccc
- Text ddd
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- sometime ago
- Formules chimiques (testen-02)
A petit article dans Chemistry
Confirmation à l’essai pour fer II
3K3[Fe(CN)6] + 3Fe^2+ -> 3KFe(ii)[Fe(iii)(CN)6]”|v” + 6K^+Curcumin
`\`/<`\H3C`O>|<`/HO>\/`|_o/\/<`||O>\/<`||O>\//\/\(*/`OCH3*)|<\OH>`/`\`|_o
…….. Encore une fois ….
A petit article dans Chemistry
Confirmation à l’essai pour fer II
3K3[Fe(CN)6] + 3Fe^2+ -> 3KFe(ii)[Fe(iii)(CN)6]”|v” + 6K^+Curcumin
`\`/<`\H3C`O>|<`/HO>\/`|_o/\/<`||O>\/<`||O>\//\/\(*/`OCH3*)|<\OH>`/`\`|_o
…….. Encore une fois ….
H2O ouH2SO4/\OHce qui et Ce qui - 1
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- À Cette Le poste Il vient Les tout entier question, Mais c’est En un mot formuléÀ Cette Le poste Il vient Les nouveaux question, Mais c'est aussi une Mise à jour est Bien sûr possible. Poursuite Le question (dans le Fichiers d'entrée) à une Les nouveaux La ligne. Par ailleurs, peuvent être explicite Coupe des lignes réalisé sont: (testen-03)
Il s'agit Autres est Les produits chimiques La notation relativement tout simplement: Fe3+, SO2-4, 235U, ^235 U (Réservation de l'eau), 23692U, 6.022·1023 (devrait être tout de suite présenté sont: 6.022·1023)
Les erreurs? SO24 à l'intérieur. SO2+4 à l'intérieur. SO+24 - 1
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- divers les recensements (testen-04)
- a) … Aucune …
- b) Le texte bbb
- c) Le texte ccc
- d) Le texte ddd
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- b 15 (testen-15)
- Typ: Double-Dreieck
- … Un double triangle etc.. ….
- Le texte bbb
- Le texte ccc
- Le texte ddd
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- sometime ago
- test (testen-01)Per il Parte ci sono il il seguente: Costruttori non, Ma Pagina di prova, guardare come La Presentazione Funziona:
2x, 2abc, 3·4def, 4def, 73, 7(a-b), 7(3·4)
(abc)2 , (abc)-2 , [abc]2, [abc]-2
(abc)def , (abc)-def , [abc]def, [abc]-def
72, 7-2, (7)2, (7)-2, (7)2-, [7]2, [7]2-, [7]-2, [7]2- abc
abcdef , abcdef
prodotto ionico: c(H3O+)·c(OH–) = 10-14 mol2/l2
a2 + b3 + d·e-2 = f+3 – (e33)
(a)2 + (b3) + (d·e)-2 = f+3 – (e33)
Unità … [kg/m3], m/s2, [mol/l]–, g/cm3
Ableitungen1 -d[Br2]/dt = -d[H2]/dt = + 1/2·d[HBr]/dt
Ableitungen2 -1/2·d[N2O5] /D'altro canto = + 1/4·d[NO2]/dt = + d[O2]/dt
Ableitungen3 – d[A]/D'altro canto = – 1/2·d[B]/dt = + 1/3·d[C]/dt = + 1/4·d[D]/dt
Ableitungen4 -½ d[N2O5]/dt = + 1/4 d[NO2]/dt = + d[O2]/dt
– d[A]/D'altro canto = – ½ [Db]/D'altro canto = + 1/3 d[C]/D'altro canto = + 1/4 d[D]/D'altro canto
E-Per iscritto 5·102, 5·10-2, 5·102
Test2 c(H2SO4) > c(HSO–4 ) > c(SO2-4 )
Test3 H2SO4 > HSO–4 > SO2-4 …… SO2-4 , SO-24, SO2-4 , SO24
Test3 H2SO4 ……. HSO–4 …. SO2-4
Test4 (abc)2
Numerosi Ioni NH+4, SO2-4 , SO-24, SO2-4 , SO24, NO–3, H2PO–4
normale .. C6H12O6, H2O, CO2, e+, e–, p+, p–, 13C, Mg2+, (Mg2+), (F-), (C6H12O6)
Cereali: 1H, 4He, 92U, 73Li, 42He2+, 42He+2
Beta meno: 10n → 11p + 0-1e–
Beta-Plus: 11p → 10n + 01e+
Numerosi Ioni NH+4, SO2-4 , SO-24, SO2-4 , SO24, NO–3, H2PO–4
… Altri più CO2-3 , CO-23 , HCO–3 , HSO–4 , OH–, H3O+, (H3O+) , H3O+
Carri più carichi Na+ / Na2+ / Na+2 / Na3+ / Na+3 / 92U+ / 92U2+ / 92U+2
– caricazioni Br– / Br2- / Br-2 / Br3- / Br-3 / Br4- / O– / O-1 / O1-
diversi tipi di =header= _abs_ e–, ee–, ab–, AB–, CDE–, CDe–, p+, Br– , Na+, Cl–, H3O+, OH–,
Complesso [Fe(H2O)6]–, [Fe(H2O)6]3-, [Fe(H2O)6]-3,[Fe(H2O)6]+, [Fe(H2O)6]2+, [FeS]2+, [FeS2]2
Complesso2 [Fe(H2O)6]x, [Fe(H2O)6]y,[Fe(H2O)6]?
Test pH = log(c(H3O+)), 82Br–,
Fabbricazioni per macchi (13C), ( 42He), 42He, ( 42He2+), ( 42He+2), (Mg2+), (Mg+2)
termodinamica ΔHof(C6H12O6), ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
Termo 2: ΔHoR(H2O), ΔSoR(CO2), ΔSoR= So(Produkte) – So(Edukte)
Termo 3: ΔHoR(H2O), So(CO2), So(C6H12O6), So(Edukte), So(Produkte)
Termo 4: ΔSoR= So(Produkte) – So(Edukte)
Termo 4a: ΔSoR = So(H2O)
Termo 5: dG = dH – T·dS
Termo 6: ΔGoR = ΔHoR – T· ΔSoR
Termo 7: ΔGoR, ΔGoR(H2O)
E … qui dovrebbe Una Tabella Venite:Fabbrica M(g/mol) m(g) n(mol) H2O 18 100 100/18= 5.55 H2 2 2·5.55 = 11.1 5.55 O2 32 32·2.77 = 88.9 5.55 / 2 = 2.77 O3 32 32·2.77 = 88.9 5.55 / 2 = 2.77
E … qui dovrebbe Una Elenco Venite:- b) Il testo e Altri Il testo
- Il testo e Altri Il testo
- b) Il testo e Altri Il testo
- Il testo e Altri Il testo
- b) Il testo e Altri Il testo
- _@_ Il testo e Altri Il testo più
- _@_ Il testo e Altri Il testo più
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- sometime ago
- Formule chimiche (testen-02)
A piccole articolo in Chemistry
Confirmazione test per ferro II
3K3[Fe(CN)6] + 3Fe^2+ -> 3KFe(ii)[Fe(iii)(CN)6]”|v” + 6K^+Curcumin
`\`/<`\H3C`O>|<`/HO>\/`|_o/\/<`||O>\/<`||O>\//\/\(*/`OCH3*)|<\OH>`/`\`|_o
…….. Ancora una volta ….
A piccole articolo in Chemistry
Confirmazione test per ferro II
3K3[Fe(CN)6] + 3Fe^2+ -> 3KFe(ii)[Fe(iii)(CN)6]”|v” + 6K^+Curcumin
`\`/<`\H3C`O>|<`/HO>\/`|_o/\/<`||O>\/<`||O>\//\/\(*/`OCH3*)|<\OH>`/`\`|_o
…….. Ancora una volta ….
H2O oH2SO4/\OHQuesto e che - 1
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- In particolare: di questo Posizione Vieni La intera domanda, Ma In breve formulatoIn particolare: di questo Posizione Vieni La Nuovi domanda, Ma anche una aggiornamento è Naturalmente possibili. Continuare Il domanda (in File di input) su una delle Nuovi Linea. Anche possono essere esplicito Interruzioni di linea Fatto essere: (testen-03)
Della Altri è La Prodotti chimici Notazione Relativamente Semplicemente: Fe3+, SO2-4, 235U, ^235 U (Scarico vuoto), 23692U, 6.022·1023 (dovrebbe In questo momento Presentazione essere: 6.022·1023)
Errori? SO24 vs. SO2+4 vs. SO+24 - 1
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- diversi Rendizioni (testen-04)
- a) … Nessuna …
- b) Il testo bbb
- c) Il testo ccc
- d) Il testo ddd
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- b 15 (testen-15)
- Typ: Double-Dreieck
- … Triangolo doppio ecc.. ….
- Il testo bbb
- Il testo ccc
- Il testo ddd
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- Test (testen-01)To the Part of is given It 's the following: Constructed not, But Test page, Looking How The Presentation It works.:
2x, 2abc, 3·4def, 4def, 73, 7(a-b), 7(3·4)
(abc)2 , (abc)-2 , [abc]2, [abc]-2
(abc)def , (abc)-def , [abc]def, [abc]-def
72, 7-2, (7)2, (7)-2, (7)2-, [7]2, [7]2-, [7]-2, [7]2- abc
abcdef , abcdef
ionic product: c(H3O+)·c(OH–) = 10-14 mol2/l2
a2 + b3 + d·e-2 = f+3 – (e33)
(a)2 + (b3) + (d·e)-2 = f+3 – (e33)
Units … [kg/m3], m/s2, [mol/l]–, g/cm3
Ableitungen1 -d[Br2]/dt = -d[H2]/dt = + 1/2·d[HBr]/dt
Ableitungen2 -1/2·d[N2O5] /(i) the number of = + 1/4·d[NO2]/dt = + d[O2]/dt
Ableitungen3 – d[A]/(i) the number of = – 1/2·d[B]/dt = + 1/3·d[C]/dt = + 1/4·d[D]/dt
Ableitungen4 -½ d[N2O5]/dt = + 1/4 d[NO2]/dt = + d[O2]/dt
– d[A]/(i) the number of = – ½ [Db]/(i) the number of = + 1/3 d[C]/(i) the number of = + 1/4 d[D]/(i) the number of
E-In writing 5·102, 5·10-2, 5·102
Test2 c(H2SO4) > c(HSO–4 ) > c(SO2-4 )
Test3 H2SO4 > HSO–4 > SO2-4 …… SO2-4 , SO-24, SO2-4 , SO24
Test3 H2SO4 ……. HSO–4 …. SO2-4
Test4 (abc)2
Multimedia Ions NH+4, SO2-4 , SO-24, SO2-4 , SO24, NO–3, H2PO–4
normal .. C6H12O6, H2O, CO2, e+, e–, p+, p–, 13C, Mg2+, (Mg2+), (F-), (C6H12O6)
Cereals: 1H, 4He, 92U, 73Li, 42He2+, 42He+2
Beta-minus: 10n → 11p + 0-1e–
Beta-Plus: 11p → 10n + 01e+
Multimedia Ions NH+4, SO2-4 , SO-24, SO2-4 , SO24, NO–3, H2PO–4
… Not yet more CO2-3 , CO-23 , HCO–3 , HSO–4 , OH–, H3O+, (H3O+) , H3O+
Additional loads Na+ / Na2+ / Na+2 / Na3+ / Na+3 / 92U+ / 92U2+ / 92U+2
Minus loads Br– / Br2- / Br-2 / Br3- / Br-3 / Br4- / O– / O-1 / O1-
Various =header= _abs_ e–, ee–, ab–, AB–, CDE–, CDe–, p+, Br– , Na+, Cl–, H3O+, OH–,
Complex [Fe(H2O)6]–, [Fe(H2O)6]3-, [Fe(H2O)6]-3,[Fe(H2O)6]+, [Fe(H2O)6]2+, [FeS]2+, [FeS2]2
Complex2 [Fe(H2O)6]x, [Fe(H2O)6]y,[Fe(H2O)6]?
Test pH = log(c(H3O+)), 82Br–,
Manufacture in which the value of all the materials used does not exceed 50% of the ex-works price of the product (13C), ( 42He), 42He, ( 42He2+), ( 42He+2), (Mg2+), (Mg+2)
thermodynamics ΔHof(C6H12O6), ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
Thermo 2: ΔHoR(H2O), ΔSoR(CO2), ΔSoR= So(Produkte) – So(Edukte)
Thermo 3: ΔHoR(H2O), So(CO2), So(C6H12O6), So(Edukte), So(Produkte)
Thermo 4: ΔSoR= So(Produkte) – So(Edukte)
Thermo 4a: ΔSoR = So(H2O)
Thermo 5: dG = dH – T·dS
Thermo 6: ΔGoR = ΔHoR – T· ΔSoR
Thermo 7: ΔGoR, ΔGoR(H2O)
And then … Here you go. should be One Table Come on .:Manufacture M(g/mol) m(g) n(mol) H2O 18 100 100/18= 5.55 H2 2 2·5.55 = 11.1 5.55 O2 32 32·2.77 = 88.9 5.55 / 2 = 2.77 O3 32 32·2.77 = 88.9 5.55 / 2 = 2.77
And then … Here you go. should be One List Come on .:- b) Text of the text and Not yet Text of the text
- Text of the text and Not yet Text of the text
- b) Text of the text and Not yet Text of the text
- Text of the text and Not yet Text of the text
- b) Text of the text and Not yet Text of the text
- _@_ Text of the text and Not yet Text of the text more
- _@_ Text of the text and Not yet Text of the text more
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- sometime ago
- Chemical formulae (testen-02)
A small the article in Chemistry
Confirmation Test for iron II
3K3[Fe(CN)6] + 3Fe^2+ -> 3KFe(ii)[Fe(iii)(CN)6]”|v” + 6K^+Curcumin
`\`/<`\H3C`O>|<`/HO>\/`|_o/\/<`||O>\/<`||O>\//\/\(*/`OCH3*)|<\OH>`/`\`|_o
…….. Once again ….
A small the article in Chemistry
Confirmation Test for iron II
3K3[Fe(CN)6] + 3Fe^2+ -> 3KFe(ii)[Fe(iii)(CN)6]”|v” + 6K^+Curcumin
`\`/<`\H3C`O>|<`/HO>\/`|_o/\/<`||O>\/<`||O>\//\/\(*/`OCH3*)|<\OH>`/`\`|_o
…….. Once again ….
H2O orH2SO4/\OHThis and This - 1
- 2
- sometime ago
- On the This Place Come on The whole question, But Just a minute FormulatedOn the This Place Come on . The new question, But also a Up to date is Of course. possible. Continued The question (In the Input files) on One of them new Line. Also can explicitly Line breaks made will be: (testen-03)
The Commission Other is The Chemical Notation Relative It 's just …: Fe3+, SO2-4, 235U, ^235 U (Damages and damage), 23692U, 6.022·1023 (should be Right now. Presented will be: 6.022·1023)
Faults? SO24 vs.. SO2+4 vs.. SO+24 - 1
- 2
- sometime ago
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