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Berechne / Ergänze die Werte in folgender Tabelle.
c(H3O+ mol/l) c(OH– mol/l) pH pOH 0.001 0.01 0.1 0.2 12 11 
Textantwort: Zur Erinnerung: Das Ionenprodukt gilt für jede Konzentration, für jeden pH resp. pOH.
Ionenprodukt: c(H3O+)·c(OH–) = 10-14 mol2/l2c(H3O+ mol/l) c(OH– mol/l) pH pOH 0.001 = 10-3 10-11 3 11 0.01 = 10-2 10-12 2 12 10-13 0.1 (10-1) 13 1 10-14/0.2 = 5·10-14 0.2 13.3 0.7 10-12 10-2= 0.01 12 2 10-3 = 0.001 10-11 3 11
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