Calculate with reaction equation 4 (st-74) By One of them reaction to be created 54 Grams Water. What ? Volumes takes This Water … … In the Liquid State of operation a? … In the Gaseous State of operation In the case of Normal conditions a? … In the Gaseous State of operation In the case of a Pressure of 3 bar and 70℃ a?

  Aufgabe: st-74    

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By One of them reaction to be created 54 Grams Water. What ? Volumes takes This Water …

1. … In the Liquid State of operation a?
2. … In the Gaseous State of operation In the case of Normal conditions a?
3. … In the Gaseous State of operation In the case of a Pressure of 3 bar and 70℃ a?

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Lösung:

1. Adopted: 1 Litre corresponds to 1 kg (Density = 1.0 g/cm³). This means that 1000 Milligrams 1000 Grams. So what ? 54 Milligrams.
2. By Normal conditions (0℃ and Normal pressure) takes a of any kind Gas (also Water in Form of Water vapour) for each Mol 22.4 Litre a. With n = m/M(H₂O=) = 54 / 18 = 3 mol is given The Commission a Volumes of 3·22.4=67.2 Of which:.
3. With pV=nRT is given The Commission for (n = 1 mol) a V = nRT/p = (1 mol · 8.314 JmolK · (273+70)K) / (3·101300 N/m²⁾ = 0.00938 m³ Responsibility. 9.38 Litre (for each mol) and This means that for 3 mol (Look at this. exercise b) a Volumes of 28.2 Litre.

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