Chemical equilibrium, speed rates (GW-04) We're going to give you the following reactions, and we're going to give you the same reaction, so… … whole (!) numbers as coefficients … for each substance its rate of velocity (d[X]/dt) is given. a) Br2 + H2 ⇄ HBr b) N2O5 → NO2 + O2 (c) A + 2 B → 3 C + 4 D (already balanced!)

  Exercise: GW-04    

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We're going to give you the following reactions, and we're going to give you the same reaction, so…
… whole (!) numbers as coefficients
… for each substance its rate of velocity (d[X]/dt) is given.
a) Br₂ + H₂ ⇄ HBr
b) N₂O₅ → NO₂ + O₂
(c) A + 2 B → 3 C + 4 D (already balanced!)

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Solution:

a) Br₂ + H₂ ⇄ 2·HBr

    -d[Br₂]/dt = -d[H₂]/dt = + 1/2·d[HBr]/dt

b) 2·N₂O₅ → 4·NO₂ + 1·O₂

    -1/2·d[N₂O₅]/dt = + 1/4·d[NO₂]/dt = + d[O₂]/dt

c) A + 2·B → 3·C + 4·D

    – d[A]/dt = -1/2·d/dt = + 1/3·d[C]/dt = + 1/4·d[D]/dt

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