Concentration, exercise 10 (st-93) Calculate The Concentration of Household sugar (C12H22O11), in One of them Cup Coffee (150 Milligrams), where: in it. a WOther sugar (m = 7.7 g) dissolved will be. Additionally: How many molecules Caffeine (C8H10N4O2) are The Commission after a Coffee In the KManufacture, where: in One of them Cup Coffee 80 mg of which: dissolved were?

  Aufgabe: st-93    

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Calculate The Concentration of Household sugar (C₁₂H₂₂O₁₁), in One of them Cup Coffee (150 Milligrams), where: in it. a WOther sugar (m = 7.7 g) dissolved will be.
Additionally: How many molecules Caffeine (C₈H₁₀N₄O₂) are The Commission after a Coffee In the KManufacture, where: in One of them Cup Coffee 80 mg of which: dissolved were?

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Lösung:

1. c = n/V = m/M/V
       M(C₁₂H₂₂O₁₁) = 342 g/mol
       c = 7.7g/342g/mol / 0.15 L = 0.15 mol/L
2. Additional task:
3. n = m/M
       M(C₈H₁₀N₄O₂) = 194 g/mol
       · n = 0.08/194 = 0.000412 mol = 4.12·10^-4 mol
       · 1 mol = 6.022·10²³
       · 4.12·10^-4 mol → 2.48·10²⁰

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