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Different calculations round to The Concentration.
- 5 Grams Fresh or chilled will be in a Litre Water given. What ? Concentration has The Lthe island?
- 18 g C6H12O6 will be in 120 Milligrams Water solved. What ? Concentration has The Lthe island?
- 10 Milligrams One of them 0.02 mol/l Vitamins C Lthe island have been Produced. What ? Weight had The weighted Weight?
Notes: M(Vitamin C) = 176.13 g/mol - Es to be 100 Milligrams One of them Magnesium bromide solution (MgBr2) with The Concentration of c = 0.02 mol/L Manufacture will be.
How can These Lthe island In the Chemical laboratory Manufacture will be? - One of them Litre One of them Cooking salt solution Weighing 1.34 kg. What ? Concentration has The Lthe island?
In order to Remembrance: c = n/V = m/M/V
Lösung: This Volumes must in Litre indicated will be.
- c = m(NaCl)/M(NaCl)/V = 5g/58.5g/mol/1.0 L = 0.085 mol/l
- c = m(C6H12O6)/M(C6H12O6)/V = 18g/180g/mol/0.12L = 0.833 mol/l
- c = n/V = m/M/V → m = c·V·M
m = 0.02 mol/l · 0.01 l · 176.13 g/mol = 0.035 g - c = n/V = m/M/V → m = c·V·M
M(MgBr2) = 184.3 g/mol
m = 0.02 mol/L · 0.1 L · 184.3 g/mol = 0.3686 g
Es must be So what do you mean? 0.3686 Grams MgBr2 weighted will be and So much Water Added will be, that This Final volume 100 Milligrams is. - Adopted: 1 Litre Water be 1.0 kg, The Remains So what do you mean? Fresh or chilled: 340 Grams
n=m(NaCl)/M(NaCl) = 340g/58.5 g/mol = 5.81 mol
c = n/V = 5.81 mol / 1.0 L = 5.81 mol/L
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