Coulomb’s law, Application 4 (Atom-23) How Changes The Commission The Strength between two Loads, where: The Distance between to them halved will be? The Loading Stay with me Right now..

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How Changes The Commission The Strength between two Loads, where: The Distance between to them halved will be? The Loading Stay with me Right now..

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Lösung:

When The Distance between two Loads after to the Coulomb's law halved will be, increased The Commission The Strength between to them to This Four times. This is of this, that The Strength Otherwise Proportional to the Square of the Distance is. Therefore,, where: The Distance halved will be (Distance will be to 1/2), will be The Value of return of the Squares This Fragments (So what do you mean? 2² = 4) The new Strength In the Proportion to the of origin Strength be.

The whole The situation mathematical Presented: F_a be The Strength, which before The Changes It works, F_b The Strength after The Changes.

1. F_a =k·Q₁·Q₂ / x²
2. F_b =k·Q₁·Q₂ / (0.5·x)²
       = k·Q₁·Q₂ / (0.5²·x²)
       = k·Q₁·Q₂ / (0.25·x²)
       = k·Q₁·Q₂ / x² · 4
       = 4·F_a

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