Coulomb’s law, Application 6 (Atom-25) Two Particles with of equal value positive Loading will be from each other Distant. How modified The Commission The Strength, where: The Distance three times and The Loading One of them Particles four times will be?

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Two Particles with of equal value positive Loading will be from each other Distant. How modified The Commission The Strength, where: The Distance three times and The Loading One of them Particles four times will be?

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Lösung:

One of them. four times Loading effects One four times Stronger Strength. When At the same time But Not yet The Distance three times will be, This is it. modified The Commission by: of the Coulombs The Law The Attraction on One Number nine and In total has It's 4/9 The of origin Strength.

The whole The situation mathematical Presented: F_a be The Strength, which before The Changes It works, F_b The Strength after The Changes.

1. F_a =k·Q₁·Q₂ / x²
2. F_b =k·4·Q₁·Q₂ / (3x)²
       = k·4·Q₁·Q₂ / (9·x²)
       = k·4·Q₁·Q₂ / x² · 1/9
       = F_a · 4/9

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