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Lösung: In principle a concentration ('number of particles per volume'). H+ (or more specifically: H3O+ ) This number is in order of magnitude. 1 mol/l to 0.00000000000001 mol/l Moving is taking the Overview of the (negative tooth) logarithm, specifically: pH = -log(c[H3O+]).
This gives a range of the pH's of -log1) = -log100)= 0 up to – logs0.00000000000001) = log10-14)= 14
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