empirical formulas (st-60) Given are the following: Connections. Calculate The Percentage Shares in bulk (Percentage by weight) The Elements the following: molecules: Water Carbon dioxide CH4 NH3 C2H6O C6H12O6 H2SO4 C3H6O

  Aufgabe: st-60    

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Given are the following: Connections. Calculate The Percentage Shares in bulk (Percentage by weight) The Elements the following: molecules:

1. Water
2. Carbon dioxide
3. CH₄
4. NH₃
5. C₂H₆O
6. C₆H₁₂O₆
7. H₂SO₄
8. C₃H₆O

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Lösung:

The calculation explicitly for Water:

1. · M(H₂O) = 18 g/mol
       · H: 2·1/18 = 0.111 → 11.1%
       · O: 1·16/18 = 0.888 → 88.8%
2. · M(CO₂) = 44 g/mol
       · C: 12 / 44 = 0.273 → 27.3%
       · O: 2·16/44 = 0.727 → 72.7%

All of them Results in Table of contents Form:

Connection	M[g/mol]	C[%]	H[%]	O[%]	N[%]	S[%]
H2O	18	–	11.1	88.9	–	–
CO2	44	27.3	–	72.7	–	–
CH4	16	75.0	25.0	–	–	–
NH3	17	–	17.6	–	82.4	–
C2H6O	46	52.2	13.0	34.8	–	–
C6H12O6	180	40.0	6.7	53.3	–	–
H2SO4	98	–	2.0	65.3	–	32.7
C3H8O	58	62.1	10.3	27.6	–	–

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