Interpretation of the solubility product (Salze-71) Given is the solubility product of Lp(CaSO4) = 2·10-5 mol2/l2. Is a solution with c(Ca2+)= 10-2 mol/l and c(SO2-4) = 10-4 mol/l contains, not saturated, saturated or over-saturated? Note : The following applies (to known masses): — Saturated solution ionic product = Lp — Unsaturated solution ionic product < Lp — Supersaturated solution ionic product > Lp

  Exercise: Salze-71    

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Given is the solubility product of L_p(CaSO₄) = 2·10^-5 mol²/l². Is a solution with c(Ca²⁺)= 10^-2 mol/l and c(SO2-4) = 10^-4 mol/l contains, not saturated, saturated or over-saturated?
Note : The following applies (to known masses):
— Saturated solution ionic product = L_p
— Unsaturated solution ionic product < L_p
— Supersaturated solution ionic product > L_p

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Solution:

It shall apply:
— CaSO₄ ⇄ Ca²⁺ + SO2-4      L_p(CaSO₄) = c(Ca²⁺)·c(SO2-4)
— Ionenprodukt(CaSO₄) = 10^-2 mol/l · 10^-4 mol/l = 10^-6 mol²/l²
— Thus: 10^-6 mol²/l² < L_p (=2·10^-5 mol²/l²).
— So the solution is unsaturated.

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