law of mass action, 6 (GW-15) The Substance ONBr decomposed In the case of 500 ℃ The following masses: 2·ONBr ⇄ 2·NO + Br2 Supposedly, that It 's just … 9 Percentage of the ONBr dissolved. How Large is K, where: It 's just … with 1.0 mol ONBr Started will be?

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The Substance ONBr decomposed In the case of 500 ℃ The following masses:
2·ONBr ⇄ 2·NO + Br₂
Supposedly, that It 's just … 9 Percentage of the ONBr dissolved. How Large is K, where: It 's just … with 1.0 mol ONBr Started will be?

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Lösung:

1. Starting with 9 Percentage of 1.0 mol ONBr: 0.09 mol
2. ONBr decomposed, So what do you mean? No ROck reaction.
3. 0.09 mol ONBr → 0.09 mol NO + 0.09/2 mol Br₂
4. In the GW Applicable So what do you mean?:
5. c(ONBr) = 0.91 mol, c(NO) = 0.09 mol, c(Br₂) = 0.045 mol
6. K=c²(NO)·c(Br₂)/c²(ONBr)= 0.09² · 0.045 / (0.91)^2 = 4.4 ·10^-4 mol/l

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