LProduct of growth Calculation, Aluminium fluoride (Salze-74) This LProduct of growth of One of them Aluminium fluoride solution of which: 6.3·10-11 mol4/L4. Calculate of which:, How a lot Grams The Commission Aluminium fluoride in a Litre Water Solving.

  Aufgabe: Salze-74    

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This LProduct of growth of One of them Aluminium fluoride solution of which: 6.3·10^-11 mol⁴/L⁴. Calculate of which:, How a lot Grams The Commission Aluminium fluoride in a Litre Water Solving.

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Lösung:

Notes The Participants Ions are Al³⁺ Responsibility. F^–

1. AlF₃ ⇄ Al³⁺ + 3·F^–
2. L_p = c(Al³⁺)·c³(F^–)
3. Es Applicable for The Number of The Particles, Notes '=':
       c(AlF₃) = c(Al³⁺) = ⅓·c(F^–)      
       3·c(AlF₃) = 3·c(Al³⁺) = c(F^–)       This means that Applicable:
       c(Al³⁺) = c(AlF₃)       and:
       c(F^–) = 3·c(AlF₃)
4. L_p = c(Al³⁺)·c³(F^–) = c(AlF₃)·c³(3·c(AlF₃)) = 27·c⁴(c(AlF₃)
5. c(AlF₃) = ∜(L_p/27) = 0.00123 mol/L
6. From c=n/V=m/M/V following: …
       m = c·V·M = 1.23·10^-3 mol/L · 1 L · 84 g/mol = 0.1038 g

Es Solving The Commission So what do you mean? maximum about. 0.1 Grams Aluminium fluoride in a Litre Water. This Salt is Not good Soluble in Water.

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