Manufacture One of them specified Concentration (SB-40) Descriptions The Manufacture the following: LManufacture in which all the materials used are: In the Laboratory. This LVegetable products be Always Distilled Water. Adopted The Substances are as salts of which: and Solving The Commission fully in Water. a) 1 Litre One of them 0.3 M NaOH-Lthe island b) 1 Litre One of them 0.4 M HCL-Lthe island c) 25 Milligrams 0.5 M NaOH-Lthe island d) 30 Milligrams 0.6 M H2SO4

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Descriptions The Manufacture the following: LManufacture in which all the materials used are: In the Laboratory. This LVegetable products be Always Distilled Water.
Adopted The Substances are as salts of which: and Solving The Commission fully in Water.

1. a) 1 Litre One of them 0.3 M NaOH-Lthe island
2. b) 1 Litre One of them 0.4 M HCL-Lthe island
3. c) 25 Milligrams 0.5 M NaOH-Lthe island
4. d) 30 Milligrams 0.6 M H₂SO₄

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Lösung:

The Abbreviation 'M' is a Notes on The Concentration, This is it. That's right. z.B. 0.3 M, that 0.3 mol The the following: Substance in a Litre Water solved are, Other expressed as: 0.3 mol/l
With c=n/V and n=m/M following:: c=m/M/V Responsibility. m=c·V·M
Respect: Here you go. is Now This 'M' The molar mass ! The Commission after The situation is This 'M' for Concentration or The molar mass !

Action to be taken to the Manufacture The Lthe island: The Solids, z.B. NaOH will be weighted, in a z.B. Glass of glass given and So much Distilled Water Admitted How desired. Please note:, that The Solids a small Own volume claimed, This But not Taken into account will be must.

1. a) m(NaOH)=c(NaOH)·V·M(NaOH) = 0.3 mol/l · 1.0 l · 58.5 g/mol = 17.55 g
       Es will be So what do you mean? 17.55 g NaOH weighted and with Distilled Water This Glass of glass to to the Marking of 1.0 Litre Filled.
2. b) m(HCl)=c(HCl)·V·M(HCl) = 0.4 mol/l· 1.0 l · 36.5 g/mol = 14.6 g
       You can must So what do you mean? 14.6 Grams HCl Weighing and with Distilled Water This Glass of glass to to the Marking of 1.0 Litre Filling up.
3. c) m(NaOH)=c(NaOH)·V·M(NaOH) = 0.5 mol/l · 0.025 l · 58.5 g/mol = 0.73 g
       Weighing of 0.73 g NaOH and with This is the. Water to to the Marking of 25 Milligrams Filling up.
4. d) m(H₂SO₄) = c(H₂SO₄) · V · M(H₂SO₄) = 0.6 mol/l · 0.03 l · 98 g/mol = 1.764 g
       Weighing of 1.764 g H₂SO₄ and with This is the. Water to to the Marking of 30 Milligrams Filling up.

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