This topic has 1 reply, 1 voice, and was last updated 3 months ago by .Viewing 2 posts - 1 through 2 (of 2 total)AuthorPosts April 23, 2024 at 4:00 pm #3042 Frage: (st-16) ⓘ 🖶 ausdrucken [klick Frage/Antwort] ◀ – ▶ Berechne die Molmasse folgender Verbindungen: Wasser Kohlendioxid C6H12O6 NaCl April 23, 2024 at 4:00 pm #3043 Textantwort: M(H2O): 2·M(H) + 1·M(O) = 2·1+1·16 = 18 g/mol M(CO2): 1·M(C) + 2·M(O) = 1·12+2·16= 44 g/mol M(C6H12O6): 6·M(C) + 12·M(H) + 6·M(O) = 6+12+12·1+6·16 = 180 g/mol M(NaCl): M(Na+) + M(Cl–) = 23.0 +35.5 = 58.5 g/mol Videoantwort: Erklärung in Form eines Videos, Dauer 7:22 Direkter Link zum Fullscreen-Modus hier Mitschrift: Leider keine Mitschrift des Videos vorhanden.AuthorPostsViewing 2 posts - 1 through 2 (of 2 total)You must be logged in to reply to this topic.Log In Username: Password: Keep me signed in Log In Warning: Trying to access array offset on value of type bool in /home/httpd/vhosts/rainer.ch/www_chemieaufgaben_ch/wp1/wp-content/plugins/bbp-style-pack/includes/functions.php on line 2502 Log in / Register