Most stable ions (Salze-10) The following atoms are given: aluminium, fluorine, 4Be, potassium, 52Te, neon, calcium, sulphur and nitrogen. Determine the number of valence electrons from each atom and then determine the most common ion.

  Exercise: Salze-10    

ⓘ    🔄 Reload     🖨️ print           ◀  –   ▶     ?! Question/Answer ?!

The following atoms are given: aluminium, fluorine, ₄Be, potassium, ₅₂Te, neon, calcium, sulphur and nitrogen.
Determine the number of valence electrons from each atom and then determine the most common ion.

---

Solution:

The atoms (respectively their ions) tend to reach a fully filled outermost valence shell, which can be achieved by absorbing or emitting an appropriate number of electrons.
There not of any kind many electrons included – payment are can (the ion must yes also still stable be) holds the rule, that the '[translation unavailable] of the small expenditure' committed is. This means that a particle with 3 valence electrons gives off 3 e^– and does not take up 5 e^– to achieve a completely full (8 e^-) or empty (0 e^-) valence shell.
At 4 valence electrons can both situations expected are, z.B. C⁴⁺ or C^4-

atom	number of valence electrons	uptake – release	ion
Al	3	Taxation 3 e–	Al3+
F	7	Inclusion 1 e–	F–
4Be	2	Payment 2 e–	Be2+
K	1	Tax 1 e–	K+
52Te	6	Admission 2 e–	Te-2
Ne	8	Neither	Ne
Ca	2	Payment 2 e–	Ca2+
S	6	Admission 2 e–	S2-
N	5	Admission 3 e–	N3-

[Author]

Posts