Number of Elements (st-02) Calculate in each case The Number of of all Participants Elements the following: Expressions. This first Example is Yes, I did. solved. a) H2O: 2·H, 1·O b) Carbon dioxide c) C6H12O6 d) 7·H2O e) 40·C6H12O6 f) 3 A dozen NH3 g) 7 Millions O3 (=Ozone) h) 2 mol H2O i) 13 mol N2

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Calculate in each case The Number of of all Participants Elements the following: Expressions. This first Example is Yes, I did. solved.

1. a) H₂O: 2·H, 1·O
2. b) Carbon dioxide
3. c) C₆H₁₂O₆
4. d) 7·H₂O
5. e) 40·C₆H₁₂O₆
6. f) 3 A dozen NH₃
7. g) 7 Millions O₃ (=Ozone)
8. h) 2 mol H₂O
9. i) 13 mol N₂

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Hinweis: 1 mol corresponds to to the Large A dozen The Chemists: 6.022·10²³.

Lösung:

1. a) Water = H₂O, Number of: 2·H, 1·O
2. b) Carbon dioxide = CO₂, Number of: 1·C, 2·O
3. c) C₆H₁₂O₆, Number of: 6·C, 12·H, 6·O
4. d) 7·H₂O, Number of: 14·H, 7·O
5. e) 40·C₆H₁₂O₆, Number of: 240·C, 480·H, 240·O
6. f) 1 A dozen = 12 Piece of work, This means that: 36 NH₃; Number of: 36·N, 108·H
7. g) 7 Millions O₃ = 7·10⁶ O₃ = 21 Millions O-Atoms = 21·10⁶·O = 2.1·10⁷·O
8. h) 2 mol H₂O, Number of: 4 mol H, 2 mol O (H: 2.4·10²⁴, O: 1.2·10²⁴)
9. i) 13 mol N₂, Number of: 26 mol N (=1.56·10²⁵)

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Videoantwort:
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