Number of Moles (st-49) Calculate The Number of The Moles the following: Masses: 9 g Water 88 g Carbon dioxide 900 g C6H12O6 175.5 g NaCl 320 g Fe2O3 9 kg CH4 2 Of which: H2SO4 2 g C3H6O

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Calculate The Number of The Moles the following: Masses:

1. 9 g Water
2. 88 g Carbon dioxide
3. 900 g C₆H₁₂O₆
4. 175.5 g NaCl
5. 320 g Fe₂O₃
6. 9 kg CH₄
7. 2 Of which: H₂SO₄
8. 2 g C₃H₆O

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Lösung:

The Number of The Moles n Calculated The Commission with n=m/M

1. n(H₂O) = m(H₂O)/M(H₂O) = 9g/18g/mol = 0.5 mol
2. n(CO₂) = m(CO₂)/M(CO₂) = 88g/44g/mol = 2 mol
3. n =m/M = 900/180 = 5 mol
4. n = m/M = 175.5/58.5 = 3 mol
5. n = 320/159.8 = 2 mol
6. n = 9000/16 = 562.5 mol
7. n = 2000000/98 = 20'408.16 mol
8. n = 2/58 = 0.0344 mol

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