pH-calculations, 1 (SB-47) Calculate The pH-Values the following: LManufacture in which all the materials used are:, This LVegetable products be Always of a purity Water: 1 g Hydrochloric acid (HCl) solved in a Litre Water 1 kg Hydrochloric acid (HCl) solved in a Cubic metres Water 1 g NaOH, solved in a 2 Litre Water 81 mg HBr in 0.1 Litre Water 1 Grams Sulphuric acid in 1 m3 Water. Adopted: complete Deprotonation The Sulphuric acid.

  Aufgabe: SB-47    

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Calculate The pH-Values the following: LManufacture in which all the materials used are:, This LVegetable products be Always of a purity Water:

1. 1 g Hydrochloric acid (HCl) solved in a Litre Water
2. 1 kg Hydrochloric acid (HCl) solved in a Cubic metres Water
3. 1 g NaOH, solved in a 2 Litre Water
4. 81 mg HBr in 0.1 Litre Water
5. 1 Grams Sulphuric acid in 1 m³ Water. Adopted: complete Deprotonation The Sulphuric acid.

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Lösung:

Notes 1: HCl is One heavy SYour (pKs < 0), d.h. It 's decomposed in Water fully to H₃O⁺ and Cl^–.
Notes 2: pH = -log(c(H₃O⁺)) = -log(n/V)
Notes 3: pH + pOH = 14
Notes 4: HBr is also One heavy SYour

1. a) pH = -log(1/36.5/1) = 1.56
2. b) pH = -log(1000/36.5/1000) = 1.56
3. c) pOH = -log(1/40/2) = 1.90, pH = 14 – pOH = 12.1
4. d) pH = -log(0.081/81/0.1) = 2
5. e) Sulphuric acid, H₂SO₄ is given two H⁺ from!
       pH = -log(2·1/98/1000) = 4.69

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