pH-calculations, 4 (SB-62) Given be in each case a Litre of two LManufacture in which all the materials used are: A and B with to the equal to Starting-pH of 4.8. A be One Saltic acid solution, B One Acetic acid solution. Well, you know what? will be to each Lthe island a Litre Water Admitted. Calculate The new pH-Value The Lthe island A and B By which Lthe island has It's One Greater Changes of the pH-Values, Reasons Notes: HCl is One heavy SYour (pKs < 0), Acetic acid One Weak SYour (pKs > 0)

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Given be in each case a Litre of two LManufacture in which all the materials used are: A and B with to the equal to Starting-pH of 4.8. A be One Saltic acid solution, B One Acetic acid solution.
Well, you know what? will be to each Lthe island a Litre Water Admitted.

1. Calculate The new pH-Value The Lthe island A and B
2. By which Lthe island has It's One Greater Changes of the pH-Values, Reasons

Notes: HCl is One heavy SYour (pKs < 0), Acetic acid One Weak SYour (pKs > 0)

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Lösung:

Based on: From the pH-Value can Now for The heavy SYour HCl and for The Weak SYour Acetic acid The Concentration Calculated will be:

1. It 's strong . SYour: HCl
   pH = -log(c(H₃O⁺)), c(H₃O⁺) = 10^-pH = 0.000015 mol/l
   c = n/V Responsibility. n = c · V
   n = 0.000015 · 1.0 l = 0.000015 mol
2. Weak SYour: Acetic acid
   pH = 1/2(pKs-log(HA)), c(HA) = …
   n = c·V =
3. Well, you know what? will be to each Lthe island 1 Litre of a purity Water Admitted, with c=n/V is given The Commission This means that the following:
4. HCl: pH = -log(c(H₃O⁺)) = -log(n/V)
   pH = He lied.

… Not yet not Finished ! ….

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