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Given H2 and He. Which of these two substances has the higher boiling point?
Solution: Es [translation unavailable] only VdW-powers before, the number the electrons is each 2 electrons. Since the number of the electrons is the same (or would be very similar for other examples) a prediction must be made over the surface of the H2 or He in this case.
In principle, the diameter (or radius) of an atom in PSE decreases from left to right, i.e. r(H) > r(He). Thus holds [translation unavailable] also the following:: Oberfläche(H2) > Oberfläche(He).
Since the electrons can now be better distributed on the larger surface and thus the VdW force is weakened, Sdp(H2) > Sdp(He) applies. The experiment also confirms this assumption (Sdp(H2) = -253℃ Sdp(He) = -269℃
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