reaction enthalpy Calculation 5 (thermo-17) To the Sweating and Cutting Required It's a Fuel gas. Mostly takes It's In addition Ethnicity (C2H2). Why ? takes It's not This Cheaper Methane (CH4)? Notes: Formulation for Both Gases The Combustion reaction and determining for each (!) molecule C2H2 Responsibility. CH4 The reaction enthalpy! ΔHof(CH4) = -75 kJ/mol ΔHof(C2H2) = 227 kJ/mol ΔHof(H2O) = -285 kJ/mol ΔHof(CO2) = -393 kJ/mol

  Aufgabe: thermo-17    

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To the Sweating and Cutting Required It's a Fuel gas. Mostly takes It's In addition Ethnicity (C₂H₂). Why ? takes It's not This Cheaper Methane (CH₄)?
Notes: Formulation for Both Gases The Combustion reaction and determining for each (!) molecule C₂H₂ Responsibility. CH₄ The reaction enthalpy!
ΔHof(CH₄) = -75 kJ/mol
ΔHof(C₂H₂) = 227 kJ/mol
ΔHof(H₂O) = -285 kJ/mol
ΔHof(CO₂) = -393 kJ/mol

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Lösung:

1. Incineration of Ethnicity:
   1·C₂H₂(g) + 5/2·O₂(g) → 1·H₂O(g) + 2·CO₂(g)
   ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
   ΔHoR = (1·-285+2·-393)-(1·227+5/2·0) = -1298 kJ/mol
2. Incineration of Methane:
   1·CH₄(g) + 2·O₂(g) → 2·H₂O(g) + 1·CO₂(g)
   ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
   ΔHoR = (2·-285+1·-393)-(1·-75+2·0) = -880 kJ/mol

The Accounts shows, that for each Turnover One of them Manufacture in which all the materials used are: Ethins approximately 1.5 I 'll take it . more Energy Released will be as At the same time, Methane.

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