reaction enthalpy Calculation 7 (thermo-19) Supposedly, It's decides The Commission for The not health Variation, that The complete daily Energy intake by: drinking of Alcohol (40% Alcohol) Implemented will be. Es Apply the following: Assumptions and Specifications: Alcohol for drinking would be C2H5OH (Ethanol), Density of of a purely Alcohol be 0.9 g/ml Adopted: The Alcohol will be In the KManufacture inhaled, d.h. with O2 Implemented. Notes 1: Calculate first. The reaction enthalpy, Including state of matter Notes 2: Calculate from ΔHoR and The Quantity Ethanol for each Litre Alcohol The required Quantity, to The Energy supply to to realise Notes 3: The daily Energy requirements of which: 9200 KJ Notes 4: FThe Commission shall adopt a decision. The Professionals: The Bases of calculation is not fully, In fact, I have to . The free of charge reaction enthalpy In the case of KHeat and temperature Calculated will be. Look at this. Details the following exercise thermo-108. You can Seeing But, that This Results The Commission It 's just … to about. 10 Percentage Changes would be

  Aufgabe: thermo-19    

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Supposedly, It's decides The Commission for The not health Variation, that The complete daily Energy intake by: drinking of Alcohol (40% Alcohol) Implemented will be. Es Apply the following: Assumptions and Specifications:

1. Alcohol for drinking would be C₂H₅OH (Ethanol), Density of of a purely Alcohol be 0.9 g/ml
2. Adopted: The Alcohol will be In the KManufacture inhaled, d.h. with O₂ Implemented.
3. Notes 1: Calculate first. The reaction enthalpy, Including state of matter
4. Notes 2: Calculate from ΔHoR and The Quantity Ethanol for each Litre Alcohol The required Quantity, to The Energy supply to to realise
5. Notes 3: The daily Energy requirements of which: 9200 KJ
6. Notes 4: FThe Commission shall adopt a decision. The Professionals: The Bases of calculation is not fully, In fact, I have to . The free of charge reaction enthalpy In the case of KHeat and temperature Calculated will be. Look at this. Details the following exercise thermo-108. You can Seeing But, that This Results The Commission It 's just … to about. 10 Percentage Changes would be

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Lösung:

1. reaction equation:
       1·C₂H₅OH + 3·O₂ ⇄ 2·CO₂(g) + 3·H₂O(l)
2. ΔHoR = ∑ΔHof(Produkte) – ∑ΔHof(Edukte)
   ΔHoR = (2· ΔHof(CO₂(g)) + 3 ΔHof(H₂O(l))) – ( ΔHof(C₂H₅OH) + 3· ΔHof(O₂))
   ΔHoR = (2·-393 + 3·-286) – (-278 + 3·0) = -1366 kJ/mol
   This means that Weiss It's Now, that for each Mol Ethanol 1366 KJ Released will be
3. NThe real thing to Resolving question: How a lot Grams Ethanol are In the Alcohol?
   1 Litre Alcohol, 40%, d.h. 400 Milligrams Purely Ethanol. With The Density of 0.9 g/ml to be given The Commission This means that 360 Grams Ethanol
4. M(C₂H₅OH) = 46 g/mol, This means that
   n= m/M = 360 / 46 = 7.8 mol
5. Proposed Bottle Alcohol are This means that 7.8 mol à -1366 KJ, So what do you mean? – 10690 KJ contained
6. FThe Commission shall adopt a decision. One Daily needs of 9200 KJ needs It 's So what do you mean? about. 860 Milligrams

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