This topic has 1 reply, 1 voice, and was last updated 3 months, 1 week ago by .Viewing 2 posts - 1 through 2 (of 2 total)AuthorPosts May 7, 2024 at 6:11 pm #3296 Frage: (thermo-102) ⓘ 🖶 ausdrucken [klick Frage/Antwort] ◀ – ▶ Beim Umsatz von 60 Gramm Traubenzucker werden x kJ frei. Berechne daraus die ΔHof. May 7, 2024 at 6:11 pm #3297 Textantwort: M(Traubenzucker) = M(C6H12O6) = 180 Gramm Mit 60 g C6H12O6 x kJ, bei einem Mol (=180 g) somit 3·x. ΔHof(C6H12O6) = 3·x kJ/mol.AuthorPostsViewing 2 posts - 1 through 2 (of 2 total)You must be logged in to reply to this topic.Log In Username: Password: Keep me signed in Log In Warning: Trying to access array offset on value of type bool in /home/httpd/vhosts/rainer.ch/www_chemieaufgaben_ch/wp1/wp-content/plugins/bbp-style-pack/includes/functions.php on line 2502 Log in / Register