redox, Redux table, exercise 2 (Redox-29) Assessments on the basis The Redux table, whether or not the following: reactions possible are. Ag in Copper sulphate Silver nitrate in Copper You can Let it go. (basic) Bromine with Iron and steel reacting. Bromine Lying In the Excess before. Magnesium in 1 M HCl How can from Silver nitrate This Silver in more solid Form gained will be. As Aids are It 's just … Sof which: or bases permitted. Gold It should be in One of them Lthe island dissolved will be. Give it away One Suitable Variation to.

  Aufgabe: Redox-29    

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Assessments on the basis The Redux table, whether or not the following: reactions possible are.

1. Ag in Copper sulphate
2. Silver nitrate in Copper
3. You can Let it go. (basic) Bromine with Iron and steel reacting. Bromine Lying In the Excess before.
4. Magnesium in 1 M HCl
5. How can from Silver nitrate This Silver in more solid Form gained will be. As Aids are It 's just … Sof which: or bases permitted.
6. Gold It should be in One of them Lthe island dissolved will be. Give it away One Suitable Variation to.

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Lösung:

1. Copper sulphate: CuSO₄ So what do you mean? Cu²⁺ and SO2-4
       SO2-4 Viewers, Involved The Commission not
       Ag + Cu²⁺ → Ag⁺ + Cu ??
       Redux table of Left side -> on the right Interpreting
       Mountain reaction, Voluntary not possible
2. Silver nitrate: AgNO₃ So what do you mean? Ag+ and NO–3
       NO–3 Viewers, Involved The Commission not
       Cu + Ag⁺ → Cu²⁺ + Ag ??
       Redux table of Left side -> on the right Interpreting
       Mountaineering reaction, Voluntary reaction
3. Extracts from Table of electrode potential:
       Fe → Fe²⁺ (-0.44)
       2·Br^– → Br₂ (+1.07)
       This means that: Fe + Br₂ → 2·Br^– + Fe²⁺
       But … … It 's Goes Not yet Continued:
       Fe²⁺ → Fe³⁺ (+0.75)
       This means that: Fe + Br₂ → 2·Br^– + Fe³⁺
       Load balancing: 2·Fe + 3·Br₂ → 6·Br^– + 2·Fe³⁺
4. In order to Remembrance: 1 M HCl
             → Cl^– (Viewers)
             → H₃O⁺
       Mg → Mg²⁺ (-2.37 V)
       H₂ + 2·H₂O → 2·H₃O⁺ (0.00)
       Mg + 2·H₃O⁺ → H₂ + 2·H₂O + Mg²⁺
       Mountaineering reaction, Voluntary reaction
       Magnesium Resolves The Commission on, It 's It is The Commission H₂ Gas
5. Silver nitrate: AgNO₃ So what do you mean? Ag+ and NO–3
       Required: Ag⁺ → Ag
       In of our own Case in point is Ag⁺ So what do you mean? This oxidizing agent !
       Searched are reducing agent (SYour or base)
       Available is But It 's just … The base (OH^-)
       4 OH^– → O₂ + 2·H₂O (0.4 V)
       Ag → Ag⁺ (0.8 V)
       Accrued reaction: 4 OH^– + Ag⁺ → O₂ + 2·H₂O + Ag
       According to Redox table is given It 's of which: Gold Not yet the following: Voluntary Mining operations:
       Au → Au³⁺ (1.42 V)
       Mn²⁺ + 12 H₂O → MnO–4 + 8·H₃O⁺ (1.51 V)
       PbSO₄ + 5 H₂O → PbO₂ + HSO–4 + 3·H₃O⁺ (1.68 V)
       2 F^– → F₂ (2.87 V)
       According to exercise It should be One Lthe island Manufacture will be. The reaction with F₂ would be Theoretically possible, However, It is The Commission a Salt. Therefore, are It 's just … The Variants with 1.51 V Responsibility. 1.68 V correctly.
       Au + MnO–4 + 8·H₃O⁺ → Au³⁺ + Mn²⁺ + 12 H₂O … or
       Au + PbO₂ + HSO–4 + 3·H₃O⁺ → Au³⁺ + PbSO₄ + 5 H₂O

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